2-chloropropane is synthesized by reacting propene with hydrogen chloride.HHCH+ H-CI:HHHH :C1: HH-C-C-C-HH H HUse bond energies to find the enthalpy change for this reaction. Round your answer to 3 significant figures.Note: Reference the Bond energies table for additional information.

Answered: 2-chloropropane is synthesized by…

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter23: Carbon: Not Just Another Element

Section: Chapter Questions

Problem 119SCQ

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The reaction between methanol and hydrochloric acid yields chloromethane and water. What is the enthalpy for the reaction using the given bond energies (kJ mol-1)? C-Cl = 326 H-O = 463 H-Cl = 431 C-O = 335 -511 kJ mol-1 -59 kJ mol-1 -23 kJ mol-1 -42 kJ mol-1 The reaction between methanol and hydrochloric acid yields chloromethane and water. What is the enthalpy for the reaction using the given bond energies (kJ mol-1)? C-Cl = 326 H-O = 463 H-Cl = 431 C-O = 335 -511 kJ mol-1 -59 kJ mol-1 -23 kJ mol-1 -42 kJ mol-1
The average bond enthalpy for C-His 413 kJ/mol. 413 kJ of energy is required to break a mole of CH into atoms: CH(g)→C(g) + H(g), AH=413 kJ Using this information, and your answer from Part A, calculate the enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds in benzene. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) HA AHrxn = Value Units Submit Part D Complete previous part(s) Next > Provide Feedback 9:33 PM B. W Word Google .. Spotify .. 61°F 11/17/2021
Use the given bond dissociation energies to approximate the enthalpy change for the reaction of methane with molecular chlorine as shown in the reaction below. CH4(g) + 3Cl2₂(g) → CHCl3(g) + 3HCl(g) I BDE: C-H = 410 kJ/mol C-CI 330 kJ/mol a) -227 kJ b) -327 kJ c) -457 kJ d) +227 kJ e) + 327 kJ CI-CI = 243 kJ/mol H-CI = 432 kJ/mol H-H = 436 kJ/mol C-C= 350 kJ/mol
Parts A-C only . not graded .
Using the bond energies provided, calculate the enthalpy of the reaction (∆Hrxn, in kJ) for the combustion of methanol shown below. CH3OH(l) +3/2 O2 (g) → CO2 (g) + 2 H2O(g)
37) Use bond energies to calculate the enthalpy changes for the formation of ethane (C;H6) from ethylene (C3Ha) and hydrogen (H2). Bond energies: H'(kJ/mol): (C-H): 413, (C-C): 614, (C-C): 348, (H-H): 446. Is the reaction endo or exothermic ? H H H-c-C-H C=c H-H H H a) - 114 b) + 114 c) - 230 d) +330
Using bond energies from the table, estimate ΔH for the reaction below. The OH group on the product side is attached to a carbon.CH2=CH2(g) + H2O(g) ↔ CH3CH2OH(g) Bond Energies, kJ/mol Single Bonds H C N O S F Cl Br I H 432 C 411 346 N 386 305 167 O 459 358 201 142 S 363 272 --- --- 286 F 565 485 283 190 284 155 Cl 428 327 313 218 255 249 240 Br 362 285 243 201 217 249 216 190 I 295 213 --- 201 --- 278 208 175 149 Multiple Bonds C=C 602 C=N 615 C=O 799 CºC 835 CºN 887 CºO 1072 N=N 418 N=O 607 S=O (in SO2) 532 NºN 942 O2 494 S=O (in SO3) 469
Using bond energies and the energy change of the reaction, calculate the bond energy of the CH single bond. Do not round your answer. C4H10 is butane 2C4H10 + 13O2 → 8CO2 + 10H2O . Bond Energy(kJ/mol) C-C 346 O=O 495 C=O 805 O-H 459 Reaction energy(kJ) -5329
Calculate the Enthalpy Change (ΔH) from average bond energies, which have been listed below in KJ/mol, for the following reaction and identify the nature of the reaction: CH3COOH + CH3OH → CH3COOCH3 + H2O [C‒H: 413; C‒C: 347; C=O: 745; C=C: 614; Cl‒Cl: 239, C‒O: 358; O‒H: 467]
Consider the acid-base reaction between iodoethane (CH3CH2I) and hydroxide (-OH). CH3CH2I + OH- --> CH3CH2OH + l- Use the table of bond energies to estimate the change in enthalpy (∆H in kJ/mol) for this reaction. Think about the bonds that are broken and that are formed. This reaction is endothermic, exothermic or energy neutral Using your calculation, what can you say about the strengths of the bonds? -The bonds before the reaction are stronger than the bonds after the reaction. -The bonds after the reaction are stronger than the bonds before the reaction. or -The bonds before and after the reaction are equivalent in strength.
2-Butanol can be made by the reaction of 1-butene and water: H2 C=CH-CH,–CH3 (g) + H2O(g) → CH; CH(OH)CH2CH3 (g) a Use bond dissociation enthalpies to estimate the enthalpy change in this reaction. Bond AH (kJ/mol) H-O 463 C=C 610 H-C 413 C-C 346 358 Enthalpy change = kJ b Calculate the enthalpy change for this reaction from enthalpies of formation. Substance AƒH (kJ/mol) CH3 CH(OH)CH2 CH3 (g) -293.1 H2O(g) -241.83 H2C=CH-CH2–CH3 (g) -0.1300 Enthalpy change = kJ
True or False: This reaction is endothermic because more energy is needed to break up the reactants versus the amount given off by the products. Use the reaction and bond information to answer the question. H-H +0=C = 0 - H-C = O | O-H H2 + CO, → CH,O. Reactant bond energies: H-H is 432 kJ/mol, C=O is 799 kJ/mol Product bond energies: C-H is 413 kJ/mol, C=O is 745 kJ/mol, C-O is 358 kJ/mol, O-H is 467 kJ/mol ○ True ○ False 1

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2-chloropropane is synthesized by reacting propene with hydrogen chloride. H H C H + H-CI: H H H H :C1: H H-C-C-C-H H H H Use bond energies to find the enthalpy change for this reaction. Round your answer to 3 significant figures. Note: Reference the Bond energies table for additional information.