I have difficulty understanding heterozygous. Can you help? **Crossing Heterozygous Blood Types: An Analysis****Question 18:** Cross a woman with heterozygous type A blood with a man with heterozygous type B blood. Show a Punnett square, and give the phenotypic and genotypic ratios of their offspring.**Genotypes:**A Punnett square is presented with four squares, used to predict the blood type traits of the offspring by crossing the parents' genotypes. In this case, the woman has heterozygous A blood type (AO), and the man has heterozygous B blood type (BO).**Punnett Square Explanation:**- Each parent contributes one allele for blood type.- Possible alleles from the woman: A or O.- Possible alleles from the man: B or O.**Offspring Genotypes Derived from the Square:**1. AB2. AO3. BO4. OO**Phenotypes:**The possible blood types (phenotypes) of the offspring are:- Type AB (from AB genotype)- Type A (from AO genotype)- Type B (from BO genotype)- Type O (from OO genotype)**Phenotypic Ratios:**- 1 AB: 1 A: 1 B: 1 O**Genotypic Ratios:**- 1 AB: 1 AO: 1 BO: 1 OOThis exercise demonstrates the genetic variability possible with heterozygous blood type pairings, predicting an equal probability for each blood type.

Name: I have difficulty understanding heterozygous. Can you help? **Crossing
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: I have difficulty understanding heterozygous. Can you help? **Crossing Heterozygous Blood Types: An Analysis****Question 18:** Cross a woman with heterozygous type A blood with a man with heterozygous type B blood. Show a Punnett square, and give the

In this question, a heterozygous A blood group female is crossed with a heterozygous B blood group male. When an individual is heterozygous for a particular gene then it has one recessive allele and one dominant allele. In blood groups, recessive allele is i and dominant alleles are A and B.According to the explanation given in Step 1, the genotype of heterozygous A blood female should be IAi and genotype of heterozygous B blood group male should be IBi. The cross between them can be represented as follows: Parents: IAi X IBi F1 generation: Punnet Square: Gametes IB i IA IA IB IAi i IBi ii We can observe that after crossing IAi and IBi, we obtained four different genotypes in equal proportions. Genotypes are:IAIB, IAi, IBi, ii. The genotype ratio should be: 1:1:1:1 as all the genotypes are in equal proportion. The phenotypes produced from these genotypes should be: IAIB: AB blood group IAi: A blood group IBi: B blood group ii: O blood group We can observe from the obtained genotypes, we obtained 4 different phenotypes which are present in the offspring in equal proportions. Hence the phenotypic ratio should be: 1:1:1:1 Answer: Genotypes: IAIB, IAi, IBi, ii Genotype ratio: 1:1:1:1 Phenotypes: AB, A, B and O blood group Phenotype ratio: 1:1:1:1