16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform, CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g) 1 3 is first order in CHCl3, order in Cl₂, and order overall. Show that the following mechanism is consistent with the rate law: (1) Cl₂ (g)=2C1 (g) [fast] (2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g) [slow] (3) CC13 (g) +Cl (g) → CC14 (g) [fast]
16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform, CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g) 1 3 is first order in CHCl3, order in Cl₂, and order overall. Show that the following mechanism is consistent with the rate law: (1) Cl₂ (g)=2C1 (g) [fast] (2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g) [slow] (3) CC13 (g) +Cl (g) → CC14 (g) [fast]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform,
CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g)
1
3
is first order in CHCl3,
order in Cl₂, and
order overall. Show that the following mechanism is consistent with the rate law:
(1) Cl₂ (g)=2C1 (g)
[fast]
(2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g)
[slow]
(3) CC13 (g) +Cl (g) → CC14 (g)
[fast]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadcb027d-732c-486e-b0c8-f9f0ef7820b1%2Fb0cbd9ed-f878-4d1a-8ea9-ecf92992e72b%2Fljot1xr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform,
CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g)
1
3
is first order in CHCl3,
order in Cl₂, and
order overall. Show that the following mechanism is consistent with the rate law:
(1) Cl₂ (g)=2C1 (g)
[fast]
(2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g)
[slow]
(3) CC13 (g) +Cl (g) → CC14 (g)
[fast]
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