16. A one-tailed test (upper tail) at a .123 level of significance has a critical z value of 1.96 1.54 1.645 O 1.16
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- 7.4 Please help correct thank you1. Below are the results of 30 sixth-grade I.Q. scores. 92 95 97 100 102 106 93 95 98 100 103 108 94 97 99 100 103 108 94 97 100 100 103 108 94 97 100 101 104 109 The histogram for the raw data of 30 sixth-grade I.Q. scores is presented in the graph. 20 18 16 14 12 10 87 94 101 108 115 122 IQ scores Using statistical knowledge, state one valid observation about the distribution of data in context of the scenario. Be sure to write one complete sentence, i.e., use college-level writing, in order to earn full credit. Number of Students5/10
- 5. The sediment density (g/cm³) from water in the Red River flowing through Winnipeg, Manitoba has a distribution with mean value 2.65 and standard deviation 0.85. If 40 random samples of water are collected, what is the approximate probability that the average sample sediment density is between 2.65 and 3.00? (Retain two decimal places in all calculations.) Mean value :2.45 40 samples. P (z.u5sx<3.w)?2. please answer the qestion:8.30 The mean score for freshmen on an aptitude test at a certain college is 540, with a standard deviation of 50. Assume the means to be measured to any degree of accuracy. What is the probability that two groups selected at random, consisting of 32 and 50 students, respectively, will differ in their mean scores by a) more than 20 points b) an amount between 5 and 10 points
- 22 The average age for licensed drivers in the country is u = 42.6 years with a standard deviation of o = 12. The distribution is approximately normal. a. A researcher obtained a sample of n = 25 drivers who received parking tickets. The average age for these drivers was M = 40.5. Is this a reasonable outcome of a sample of n = 25, or is the sample mean very different from what would normally be expected? (Hint: Compute the z-score for the sample mean.) b. The same researcher also obtained a sample of n = 12 drivers who received speeding tickets. The average age for this sample was M = 34.4. Is this a reasonable outcome for a sample of n = 16, or is the sample mean very different from what would usually be expected? (Again, compute the z-score for the sample mean.)4. In a test of the hypothesis Ho : u = 10 versus H. : 4 # 10, a sample of n = I = 10.8 and standard deviation s = 3.1. 50 observations possessed mean (a) Find an interpret the p-value for this test and answer a question regarding the interpretation of the result if a = 0.10. The p-value is (Fill in the blank; round to four decimal places, as needed.) You should find one of the following useful: P(z > 2.311) z 0.0104 P(z 1.825) z 0.0340 P(z < 1.431) z 0.9238 "There is sufficient evidence to reject Họ for a = 0.10." TRUE or FALSE (Circle the correct answer.) (b) Use the rejection region approach for part A. Why is this result equivalent to the p-value method? Draw a picture and/or explain in words. You should find one of the following useful: 2, 10 1.282 z.0, 1.645 2025 1.96 01 2.326 2005 2.576 Bonus (4 points). Suppose that instead of n = 50 observations, you were only able to attain a sample of n = 15 observations. In this case, compute the test statistic and provide the recipe for…The sample of 81 of pomegranates has a mean number f seed of 695, with a standard deviation of 300 seeds.Use this to test the claim that the average number of seeds in a pomegranate is 613,with s One Tailid.f.= 00 to.0o5 = 2.639, to.01= 2.374,to.085=1.990, Significance level of D.0a. %3D %3D
- 17.34 (EX) Oligofructose and calcium absorption 1/6: Nondigestible oligosaccharides are known to stimulate calcium absorption in rats. A double-blind, randomized experiment investigated whether the consumption of oligofructose similarly stimulates calcium absorption in healthy male adolescents 14 to 16 years old. The subjects took a pill for nine days and had their calcium absorption tested on the last day. The experiment was repeated three weeks later. Some subjects received the oligofructose pill in the first round and then a pill containing sucrose (which served as a control). The order was switched for the remaining subjects. Here are the fractional calcium absorption data (in percent of intake) for 11 subjects: Subject Control 1 2 3 4 5 6 7 8 9 10 11 78.4 76.6 57.4 51.5 49.0 46.6 44.2 42.9 37.2 34.1 24.6 Oligofructose 62.0 95.1 46.5 49.4 89.7 43.8 50.3 51.6 66.6 52.7 54.0 Explain clearly why the matched pairs t test is the proper choice for this experimental design. O Because this…19. A two-tailed test at a .0694 level of significance has critical z values of -1.96 and 1.96 -.86 and .86 -1.48 and 1.48 -1.09 and 1.0911.24 question attached. Thank you for answering my question!