A normal distribution of BMCC MAT51 scores has a standard deviation of 1.6. Find the z-scores corresponding to each of the following values: (Round to 2 decimal places) a. A score that is 3.2 points above the mean. (Hint: "x - mean = 5" is 5 above the mean) 2= b. A score that is 1.6 points below the mean. Z= c. A score that is 1.39 points above the mean. 2 = d. A score that is same as the mean. 2 =
A normal distribution of BMCC MAT51 scores has a standard deviation of 1.6. Find the z-scores corresponding to each of the following values: (Round to 2 decimal places) a. A score that is 3.2 points above the mean. (Hint: "x - mean = 5" is 5 above the mean) 2= b. A score that is 1.6 points below the mean. Z= c. A score that is 1.39 points above the mean. 2 = d. A score that is same as the mean. 2 =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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6.1 1
![**Understanding Z-Scores:**
A normal distribution of BMCC MAT51 scores has a standard deviation of 1.6. Find the z-scores corresponding to each of the following values: *(Round to 2 decimal places)*
**a.** A score that is 3.2 points above the mean. *(Hint: "x - mean = 5" is 5 above the mean)*
\[ z = \_\_ \]
**b.** A score that is 1.6 points below the mean.
\[ z = \_\_ \]
**c.** A score that is 1.39 points above the mean.
\[ z = \_\_ \]
**d.** A score that is the same as the mean.
\[ z = \_\_ \]
**Explanation of Z-Scores:**
Z-scores measure how many standard deviations an element is from the mean. The formula is:
\[ z = \frac{(X - \text{mean})}{\text{standard deviation}} \]
Where:
- \( X \) is the raw score,
- The mean is the average score of the distribution,
- The standard deviation is given as 1.6 in this context.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75c99f29-b994-4b0b-a9b8-00ecf29768e8%2F280930ec-9c42-4f02-a1af-e6c2c5445ce6%2Fbejolu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Z-Scores:**
A normal distribution of BMCC MAT51 scores has a standard deviation of 1.6. Find the z-scores corresponding to each of the following values: *(Round to 2 decimal places)*
**a.** A score that is 3.2 points above the mean. *(Hint: "x - mean = 5" is 5 above the mean)*
\[ z = \_\_ \]
**b.** A score that is 1.6 points below the mean.
\[ z = \_\_ \]
**c.** A score that is 1.39 points above the mean.
\[ z = \_\_ \]
**d.** A score that is the same as the mean.
\[ z = \_\_ \]
**Explanation of Z-Scores:**
Z-scores measure how many standard deviations an element is from the mean. The formula is:
\[ z = \frac{(X - \text{mean})}{\text{standard deviation}} \]
Where:
- \( X \) is the raw score,
- The mean is the average score of the distribution,
- The standard deviation is given as 1.6 in this context.
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