The alpha level.001 has a corresponding z score of .002 O True O False
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A: Givensample size(n)=1000x=25p^=xn=251000=0.025α=1%=0.01
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A: The number of t tests for independent samples (g) is 6.
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A: Given that Left-tailed test is less than type in Alternate hypothesis H1 : µ < µ0
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A: n1=526,n2=292,x1¯=43.49,x2¯=44.49,s1=13.5,s2=15.77,α=0.05se(x1¯−x2¯)=1.1Decision rule: When p…
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Q: Find the P-value for a: a. right tailed test : b. two tailed test : a. left tailed test : 00
A: Here the Z-value is 1.6 We will use the standard Normal table for finding the p-values.
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- In this exercise, we investigate answers to the questions: How much of an effect does your roommate have on your grades? In particular, does it matter whether your roommate brings a videogame to college? A study was conducted involving n for the first semester depending on whether the student and/or the roommate brought a videogame to campus. 210 first-year students who were randomly assigned a roommate. Table 1 gives summary statistics on grade point average (GPA) Student Roommate brought videogame brought videogame Sample size Mean GPA St. Dev. No No 88 3.128 0.590 Yes No 44 3.039 0.689 No Yes 38 2.932 0.699 Yes Yes 40 2.754 0.639 Table 1 Videogames and GPA We consider the effect of neither student bringing videogames compared to both students bringing them. (a) Find a 90% confidence interval for the difference in means between students in rooms in which neither the student nor the roommate brings a videogame and students in rooms in which both the student and the roommate bring a…For a study that had 40 total participants equally distributed among the 4 groups and an MSW of 4.65, which of the following is the correct result of the Tukey’s HSD calculation (.05 alpha level)? 4.09 4.15 4.79 5.180.97 is not the answer
- As dfRC increases, what happens to the values of Cramer's V needed to achieve small, medium, and large effect sizes? a. The values depend on the sample size b. The values increase c. The values decrease d. The values stay the sameIf there are 4 scores per group and the t value is 2.34, what is the p value for a two-tailed test (to 3 decimal places)?For a population with u = 84 and o = 4, what is the z-score corresponding to X= 80? O -1,00 +1,00 O+1.25 -1.50
- Participants threw darts at a target. In one condition, they used their preferredhand; in the other condition, they used their other hand. All subjects performed inboth conditions (the order of conditions was counterbalanced). Their scores areshown below.Preferred Non-preferred12 77 911 813 1010 9a. Which kind of t-test should be used?b. Calculate the two-tailed t and p values using this t test.c. Calculate the one-tailed t and p values using this t test.A left-tailed z-test found a test statistic of z = -1.99. At a 5% level of significance, what would the correct decision be? Question 20 options: Do not reject H0 Do not reject H1 Accept H0 Reject H1 Reject H0The degrees of freedom is critical to computing the p-value for the chi-square goodness of fit. We will discuss the p-value in the next lab. The degrees of freedom for the Chi-Square goodness of fit is equal to (the number of non-zero rows in the table) - 1. The number of non-zero rows is the number of expected values that are non-zero. For example: Phenotype ... Expected ... Disease ... 234 ... Wild-type ... 6743 ... has two rows where the Expected value is non-zero. So the degrees of freedom is 2-1 = 1. Another example: Phenotype ... Expected ... Disease ... 2374 ... Wild-type ... 0 ... has one row where the Expected value is non-zero. So the degrees of freedom is 1-1 = 0. With 0 degrees of freedom, the chi-square test cannot be calculated. A third example (sex-linked): Phenotype ... Expected ... Disease-Male ... 2374 ... Disease-Female ... 9456 Wild-type-Male ... 1001 ... Wild-type-Female ... 235 ... has four rows where the Expected values are…
- Suppose a random sample of n=60 college students were surveyed and r=11 of them said that blue is their favorite color. Use a=0.05. What is the value of the sample test statistic? Find the p value. 80% of all supermarketsprices end in the digit 9 or 5. Suppose a random sample of 116 items in a suoermarket find that 87 have prices that end in 9 or 5. Use a=0.05. What is the value of the sample test statistic? Find the p value.NoneIn chi-square tests, the conventional and conservative rule is to require that the difference between the observed and expected frequency for each cell be at least 5. O True O False
