6. A house cleaning service claims that it can clean a four-bedroom house in less than 2 hours. A sample of n = 36 houses is taken and the sample mean is found to be 1.97 hours and the sample standard deviation is found to be 0.1hours. Using a 0.05 level of significance the correct conclusion is: a) reject the null because the test statistic (-1.8) is < the critical value (-1.64). b) do not reject the null because the test statistic (-1.8) is < the critical value (-1.64). c) reject the null because the test statistic (-1.8) is > the critical value (-1.96). d) do not reject the null because the test statistic (-1.8) is > the critical value (-1.96). Clear selection

6. A house cleaning service claims that it can clean a four-bedroom house in less than 2 hours. A sample of n = 36 houses is taken and the sample mean is found to be 1.97 hours and the sample standard deviation is found to be 0.1hours. Using a 0.05 level of significance the correct conclusion is: a) reject the null because the test statistic (-1.8) is < the critical value (-1.64). b) do not reject the null because the test statistic (-1.8) is < the critical value (-1.64). c) reject the null because the test statistic (-1.8) is > the critical value (-1.96). d) do not reject the null because the test statistic (-1.8) is > the critical value (-1.96). Clear selection

Name: 6. A house cleaning service claims that it can clean a four-bedroom h
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Description: 6. A house cleaning service claims that it can clean a four-bedroom house in lessthan 2 hours. A sample of n = 36 houses is taken and the sample mean is found to%3Dbe 1.97 hours and the sample standard deviation is found to be 0.1hours. Using a0.05

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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