**Physics Problem: Work and Force**A force \( F \) of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 meters. If \( F \) is perpendicular to the 4 m displacement, the work the force does is:a) 0 b) 80 c) -80 d) can't be determined**Explanation:**- **Force:** The force applied has a magnitude of 20 Newtons.- **Mass:** The mass of the object is 3 kilograms, though this is not necessary to calculate work in this scenario.- **Distance:** The object moves a distance of 4 meters.- **Direction:** The force is perpendicular to the displacement.In physics, the work \( W \) done by a force is calculated as:\[ W = F \cdot d \cdot \cos(\theta) \]Where:- \( F \) is the force magnitude,- \( d \) is the displacement,- \( \theta \) is the angle between the force and displacement vectors.Since the force is perpendicular to the displacement (\(\theta = 90^\circ\)), we have \(\cos(90^\circ) = 0\). Therefore, the work done is:\[ W = 20 \cdot 4 \cdot 0 = 0 \]Thus, the correct answer is **a) 0**.

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Description: **Physics Problem: Work and Force**A force \( F \) of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 meters. If \( F \) is perpendicular to the 4 m displacement, the work the force does is:a) 0 b) 80 c) -80 d) can't b

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16) A force F of strength 20N acts on an object of mass 3 kg as it moves a Distance of 4 meters. If F is perpendicular to the 4m displacement, the work the force does is; a) 0 b) 80 c) -80 d) can't be determined

16) A force F of strength 20N acts on an object of mass 3 kg as it moves a Distance of 4 meters. If F is perpendicular to the 4m displacement, the work the force does is; a) 0 b) 80 c) -80 d) can't be determined

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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