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16) A force F of strength 20N acts on an object of mass? kg as it moves a Distance of 4 meters. If F is perpendicular to the 4m displacement, the work the force does is; a) 0 b) 80 c) -80 d) can't be determined hp 4 03 0 Q US ☐ Nov 16

16) A force F of strength 20N acts on an object of mass? kg as it moves a Distance of 4 meters. If F is perpendicular to the 4m displacement, the work the force does is; a) 0 b) 80 c) -80 d) can't be determined hp 4 03 0 Q US ☐ Nov 16

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Statement A force \( F \) of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 meters. If \( F \) is perpendicular to the 4m displacement, the work the force does is: a) 0 b) 80 c) -80 d) can't be determined ### Solution Explanation In this scenario, since the force is perpendicular to the displacement, no work is done on the object by the force. This is because work is calculated as the dot product of force and displacement vectors, which involves the cosine of the angle between the force and displacement. If the angle is 90 degrees (perpendicular), the cosine value is zero, leading to zero work. Thus, the correct answer is: a) 0
Transcribed Image Text:### Problem Statement A force \( F \) of strength 20 N acts on an object of mass 3 kg as it moves a distance of 4 meters. If \( F \) is perpendicular to the 4m displacement, the work the force does is: a) 0 b) 80 c) -80 d) can't be determined ### Solution Explanation In this scenario, since the force is perpendicular to the displacement, no work is done on the object by the force. This is because work is calculated as the dot product of force and displacement vectors, which involves the cosine of the angle between the force and displacement. If the angle is 90 degrees (perpendicular), the cosine value is zero, leading to zero work. Thus, the correct answer is: a) 0
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