(a) How much work is done in lifting a 1.4-kg book off the floor to put it on a desk that is 0.8 m high? Use the fact that the acceleration due to gravity is g = 9.8 m/s?. (b) How much work is done in lifting a 25-lb weight 5 ft off the ground? SOLUTION (a) The force exerted is equal and opposite to that exerted by gravity, so the force is F = m s = mg = (1.4)(9.8) = dt? |N and then the work done is w = Fd = | J. SE (b) Here the force is given as F = 25 lb, so the work done is w = Fd = 25 · 5 = [ ] ft-Ib. Notice that in part (b), unlike part (a), we did not have to multiply by g because we were given the weight (which is a force) and not the mass of the object.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
EXAMPLE 1
(a) How much work is done in lifting a 1.4-kg book off the floor to put it on a desk that is 0.8 m
high? Use the fact that the acceleration due to gravity is g = 9.8 m/s?.
(b) How much work is done in lifting a 25-lb weight 5 ft off the ground?
SOLUTION
(a) The force exerted is equal and opposite to that exerted by gravity, so the force is
F = m
des
dt?
= mg = (1.4)(9.8) =
|N
and then the work done is
w = Fd =
) )c0.8) - [
J.
(b) Here the force is given as F = 25 Ib, so the work done is
w = Fd = 25 · 5 = [
ft-lb.
Notice that in part (b), unlike part (a), we did not have to multiply by g because we were given
the weight (which is a force) and not the mass of the object.
Transcribed Image Text:EXAMPLE 1 (a) How much work is done in lifting a 1.4-kg book off the floor to put it on a desk that is 0.8 m high? Use the fact that the acceleration due to gravity is g = 9.8 m/s?. (b) How much work is done in lifting a 25-lb weight 5 ft off the ground? SOLUTION (a) The force exerted is equal and opposite to that exerted by gravity, so the force is F = m des dt? = mg = (1.4)(9.8) = |N and then the work done is w = Fd = ) )c0.8) - [ J. (b) Here the force is given as F = 25 Ib, so the work done is w = Fd = 25 · 5 = [ ft-lb. Notice that in part (b), unlike part (a), we did not have to multiply by g because we were given the weight (which is a force) and not the mass of the object.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Mechanical Work done
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON