LOS AN2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity andangular acceleration of the connecting link CB at the instant shown.Ratic Diegram.Salve relativeVelocityB3 n8=45°Link BC2 fVC/B-0Vc = V/₁3 + VC/B60V/BWA14=3 radis=30"VB = WAB TAB = 3 (2) = 6 Ft/Vc4Y-Direction0 = -√₂ Sin 60° + V Sin 45°V8 Sin 60°Sinasª4507= 7.35 F=> WBC = TBCLink ABAVas7-35=3IC= 2.45 radCCWKinematic diagram(Acceleration)30NERETURNARED SORAGEnAc=AB+ A4/30A₁ = a + a² + ave,Link BCLink ABat=d. [AB=08acdeY-DinationntA₁ = a^² + 4/8 + A²4/2AB▷отив048n0 = 0 Sin 30 - O Sin 45+ ang sin 45°CIB0 = 18 Sin 30° - 18 Sin 45 + 0 Sinus→ at = 5-27 11/²WABt+0$18X-DirectionO- Vc = V8 Coabu - V₁/8 C0-45°2A² = WAB TAB = 18 F1 /₂²Vc = -6 Cos6⁰ + 7-35 C-45Vc = 2-2 Ft/₂n0₁/=|dis = dpi Toe'BCBc2.=W₁²² √ Bc = 18 F 1/5²2Cla₁8 5.27 = 1.76 a 2 cewXBC = TBCSH 4:16SearchExpert Q&ADonePlease solve question 16-109 below this in thefollwoing way:• Please include a kinamatic diagram (one forvelocity and one for acceleration).• Please DO NOT solve this using velocityanalysis (cartesian vector analysis). I wouldlike it to be solved using scalar method. Wedont use 3D in this course. We only use scalaranalysis for the relative velocity equation(writing the x and y components of theequation and solving the equations for theunknowns). I have attached a sample questionwith solution in order to get an idea on how touse the scalar method to solve my question. Iwould like question 16-109 to be solved in asimilar way. Thank you for yourunderstanding.If you can solve it as soon as possible thatwould be great and I will give you a thumps upand positive feedback :)16-109. Member AB has the angular motions shown.Determine the angular velocity and angular acceleration ofmembers CB and DC.100 mmD60°450 mmWABα AB84= 2 rad/s= 4 rad/s²=B200 mm

From given spatial representation of mechanism, points A and D are fixed points. Thus, the points A…

Answered: 16-109. Member AB has the angular…

16-109. Member AB has the angular motions shown. Determine the angular velocity and angular acceleration of members CB and DC. 100 mm C D 60° 450 mm WAB 2 rad/s %AB = 4 rad/s² B 200 mm

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Question

LOS AN
2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity and
angular acceleration of the connecting link CB at the instant shown.
Ratic Diegram.
Salve relative
Velocity
B
3 n
8=45°
Link BC
2 f
VC/B
-
0
Vc = V/₁3 + VC/B
60
V/B
WA
14=3 radis
=30"
VB = WAB TAB = 3 (2) = 6 Ft/
Vc
4
Y-Direction
0 = -√₂ Sin 60° + V Sin 45°
V8 Sin 60°
Sinasª
4507
= 7.35 F
=> WBC = TBC
Link AB
A
Vas7-35
=
3
IC
= 2.45 rad
CCW
Kinematic diagram
(Acceleration)
30
NERETURNARED SORAGE
n
Ac=AB+ A4/30
A₁ = a + a² + ave
,
Link BC
Link AB
at=d. [AB=0
8
ac
de
Y-Dination
n
t
A₁ = a^² + 4/8 + A²4/2
AB
▷
отив
048
n
0 = 0 Sin 30 - O Sin 45+ ang sin 45°
CIB
0 = 18 Sin 30° - 18 Sin 45 + 0 Sinus
→ at = 5-27 11/²
WAB
t
+0$18
X-Direction
O
- Vc = V8 Coabu - V₁/8 C0-45°
2
A² = WAB TAB = 18 F1 /₂²
Vc = -6 Cos6⁰ + 7-35 C-45
Vc = 2-2 Ft/₂
n
0₁/=
|dis = dpi Toe
'BC
Bc
2.
=W₁²² √ Bc = 18 F 1/5²2
Cla₁8 5.27 = 1.76 a 2 cew
XBC = TBC
S
H

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Step 1: Draw kinematic diagram for velocity analysis of links.

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Step 2: Apply relative velocity approach.

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Step 3: Draw kinematic diagram for acceleration analysis of links.

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Step 4: Apply relative acceleration approach.

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