13. Object X travels across ahorizontal surface and collides withobject Y. The velocity as a functionof time for object X and object Ybefore, during, and after thecollision is shown in the graph. Bothobjects have a mass of 2 kg. Whichof the following correctly describesthe momentum p of the system andthe kinetic energy KE of thesystem? *5-• Object Xo Object Y43+-1-24 ㅇ-30.20.40.60.81.0Time (s)O (A) p is conserved KE is conserved(B) p is conserved KE is not conserved(C) p is not conserved KE is conserved(C) p is not conserved KE is notconservedVelocity (m/s)

The momentum of a body can be simply defined as the mass in motion of a body. It can be written as…

Answered: 13. Object X travels across a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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In a completely inelastic collision between two objects, where the objects stick together after the collision, is it possible for the final kinetic energy of the system to be zero? If so, give an example in which this would occur. If the final kinetic energy is zero, what must the initial momentum of the system be? Is the initial kinetic energy of the system zero? Explain.
Two identical cars (m = 1350 kg) are traveling at the same speed of 20.2 m/s. They are moving in the directions shown in the drawing. What is the magnitude of the total momentum of the two cars? Magnitude of total momentum = i Save for Later North 60.0⁰ 30.0° East Attempts: 0 of 1 used Submit Answer
A two dimensional collision between a green and a purple ball, where the purple ball strikes the green. If the data for both objects' velocities (x and y components) versus time are provided, and the mass of the balls are identical, what is a way to determine if the momentum of the system conserved? Explain your methodology. Green ball: vx = 0 m/s from t = 0 s to t = 0.4 s vx = 17.42 m/s from t = 0.5 s to t = 5 s vy = 0 m/s from t = 0 s to t = 0.4 s vy = -8.01 m/s from t = 0.5 s to t = 5 s Purple ball: vx = 22.3 m/s from t = 0 s to t = 0.4 s vx = 4.878 m/s from t = 0.5 s to t = 5 s vy = 2.6 m/s from t = 0 s to t = 0.4 s vy = 10.61 m/s from t = 0.5 s to t = 5 s
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Two cars have the same mass. Car 1 is travelling northward at a speed of 45 mi/hr. Car 2 is travelling southward at a speed of 45 mi/hr. The cars a) have the same momentum and kinetic energy. b) have the same momentum but different kinetic energies. c) have different momenta but the same kinetic energy. d) Have different momenta and kinetic energy.
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Starting from rest, the acceleration of particle, which is confined to move along astraight line, is given by a = 56t 2 − 33t − 9, where x is in meters and t is inseconds. Determine (a) the time required for the particle to reach a velocity of61m/s from its initial condition at t=0, (b) the acceleration of the particle whenv=25m/s, and (c) the net displacement of the particle during the interval from t=1sto t=4s.

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