Force (N) 3 2 1. Time (s) 5 6 7! 8 -1 -2 -3 -4 -5- An object is initially at rest. A varying force is applied to the object as shown in the graph. Which of the following correctly explains the momentum of the object at time t = 7 s? The final momentum of the object is negative because the slope of the graph is negative the entire time from t = 0 s to t = 7 s. A The final momentum of the object is positive because the maximum magnitude of the force in the positive B direction is twice the maximum magnitude of the force in the negative direction. The final momentum of the object is negative because the magnitude of the area bounded by the graph and the horizontal axis is less from t = 0 s to t = 2 s than from t = 2 s tot = 7 s. The final momentum of the object is positive because the average magnitude of the force is higher from t = 0 s to t == 2 s than the average D magnitude of the force from t = 2 s to t = 7 s.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Force (N)
5-
4.
3.
1.
0-
Time (s)
6
-1
-2
-3
-4
-5.
An object is initially at rest. A varying force is applied to
the object as shown in the graph. Which of the following
correctly explains the momentum of the object at time
t = 7 s?
The final momentum of the object is
negative because the slope of the graph
is negative the entire time from t = 0 s
to t = 7 s.
The final momentum of the object is
positive because the maximum
magnitude of the force in the positive
B
direction is twice the maximum
magnitude of the force in the negative
direction.
The final momentum of the object is
negative because the magnitude of the
area bounded by the graph and the
horizontal axis is less from t = 0 s to
t = 2 s than from t = 2 s tot = 7 s.
The final momentum of the object is
positive because the average
magnitude of the force is higher from
t = 0 s to t = 2 s than the average
magnitude of the force from t = 2 s to
t = 7 s.
Transcribed Image Text:Force (N) 5- 4. 3. 1. 0- Time (s) 6 -1 -2 -3 -4 -5. An object is initially at rest. A varying force is applied to the object as shown in the graph. Which of the following correctly explains the momentum of the object at time t = 7 s? The final momentum of the object is negative because the slope of the graph is negative the entire time from t = 0 s to t = 7 s. The final momentum of the object is positive because the maximum magnitude of the force in the positive B direction is twice the maximum magnitude of the force in the negative direction. The final momentum of the object is negative because the magnitude of the area bounded by the graph and the horizontal axis is less from t = 0 s to t = 2 s than from t = 2 s tot = 7 s. The final momentum of the object is positive because the average magnitude of the force is higher from t = 0 s to t = 2 s than the average magnitude of the force from t = 2 s to t = 7 s.
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