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13. Actual sum of masses of recovered components (#6, #9, #12) 14. Actual % Recovered 15. Percent by mass of NH.CI 16. Percent by mass of SiO₂ 17. Percent by mass of NaCl 8. (014 +0.134-2.293=1.041

13. Actual sum of masses of recovered components (#6, #9, #12) 14. Actual % Recovered 15. Percent by mass of NH.CI 16. Percent by mass of SiO₂ 17. Percent by mass of NaCl 8. (014 +0.134-2.293=1.041

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Code for Unknown 2. Mass of beaker + unknown √₁ 3. 4. 5. Mass of beaker Mass of unknown Mass of beaker and residue (step 7) Mass of NHCl in unknown min-7. Mass of filter paper +SiO: Mass of filter paper Mass of SiO₂ in unknown. 6. 8 9. 10. Mass of evaporating dish + NaCl 11. Mass of evaporating dish 12. Mass of NaCl in unknown 13. Actual sum of masses of recovered components (#6, #9, #12) 14. Actual % Recovered 15. Percent by mass of NH.CI 16. Percent by mass of SiO₂ 17. Percent by mass of NaCl ample Calculations #4 - #17; 17 78.7742 77 579 1.1959 78.159.4 1.006g 47.3272 47.0349 8. (014 +0.134 - 2.293 = 1.041 (start here and add additional pages as needed)
Transcribed Image Text:1. Code for Unknown 2. Mass of beaker + unknown √₁ 3. 4. 5. Mass of beaker Mass of unknown Mass of beaker and residue (step 7) Mass of NHCl in unknown min-7. Mass of filter paper +SiO: Mass of filter paper Mass of SiO₂ in unknown. 6. 8 9. 10. Mass of evaporating dish + NaCl 11. Mass of evaporating dish 12. Mass of NaCl in unknown 13. Actual sum of masses of recovered components (#6, #9, #12) 14. Actual % Recovered 15. Percent by mass of NH.CI 16. Percent by mass of SiO₂ 17. Percent by mass of NaCl ample Calculations #4 - #17; 17 78.7742 77 579 1.1959 78.159.4 1.006g 47.3272 47.0349 8. (014 +0.134 - 2.293 = 1.041 (start here and add additional pages as needed)
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