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When burning butanol (C4H100), what mass (in g) of butanol must be reacted to produce 55.4 g of products? N.B. combustion is the reaction of a substance with molecular oxygen (O2) to produce water and carbon dioxide

When burning butanol (C4H100), what mass (in g) of butanol must be reacted to produce 55.4 g of products? N.B. combustion is the reaction of a substance with molecular oxygen (O2) to produce water and carbon dioxide

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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When burning butanol (C4H100), what mass (in g) of butanol must be reacted to produce 55.4 g of products? N.B. combustion is the reaction of a substance with molecular oxygen (O2) to produce water and carbon dioxide.

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Step 1: Introduction to the given data

Mass (in g) of butanol must be reacted to produce 55.4 g of products

The balanced equation for Combustion of Butanol C4H10O is 

C subscript 4 H subscript 10 O space plus space 6 space O subscript 2 space rightwards arrow space 4 space C O subscript 2 space plus space 5 space H subscript 2 O

Products from the Combustion is Carbon Dioxide and water 

Number of moles of CO2 and water in 55.4 g 

a) Number of Moles of CO2 :

N u m b e r space o f space m o l e s space equals fraction numerator M a s s space o f space C O subscript 2 over denominator M o l a r space M a s s end fraction equals fraction numerator 55.4 space g over denominator 44 space g divided by m o l end fraction equals 1.259 space m o l

b) Number of Moles of H2O :

N u m b e r space o f space m o l e s equals fraction numerator M a s s space o f space H subscript 2 O over denominator M o l a r space M a s s end fraction equals fraction numerator 55.4 space g over denominator 18 space g divided by m o l end fraction equals 3.078 space m o l

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