12:13 .ll LTE Question 5 of 14 Submit Determine the number of molecules of Cr2O3 that form when 1.34 x 103g of oxygen completely reacts according to the following equation: 4 Cr(s) + O2(g) → 2 Cr203(s) х STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 3 4 mol O2 mol Cr 1.34 × 103 1.68 x 1025 g Cr2O3 32.00 3.78 x 1025 mol Cr2O3 2.52 x 1025 152.00 g O2 52.00 g Cr 4.24 x 103 molecules Cr2O3 6.022 x 1023 Tap here or pull up for additional resources
12:13 .ll LTE Question 5 of 14 Submit Determine the number of molecules of Cr2O3 that form when 1.34 x 103g of oxygen completely reacts according to the following equation: 4 Cr(s) + O2(g) → 2 Cr203(s) х STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 3 4 mol O2 mol Cr 1.34 × 103 1.68 x 1025 g Cr2O3 32.00 3.78 x 1025 mol Cr2O3 2.52 x 1025 152.00 g O2 52.00 g Cr 4.24 x 103 molecules Cr2O3 6.022 x 1023 Tap here or pull up for additional resources
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![12:13
.ll LTE
Question 5 of 14
Submit
Determine the number of molecules of Cr2O3 that form
when 1.34 x 103g of oxygen completely reacts
according to the following equation:
4
Cr(s) +
O2(g) →
2
Cr203(s)
х
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
3
4
mol O2
mol Cr
1.34 × 103
1.68 x 1025
g Cr2O3
32.00
3.78 x 1025
mol Cr2O3
2.52 x 1025
152.00
g O2
52.00
g Cr
4.24 x 103
molecules Cr2O3
6.022 x 1023
Tap here or pull up for additional resources](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fedec9be0-104a-4076-a5ce-81b267ecc4b9%2F21391b84-ff31-430a-a54d-63c30011d857%2Fiqgabew.png&w=3840&q=75)
Transcribed Image Text:12:13
.ll LTE
Question 5 of 14
Submit
Determine the number of molecules of Cr2O3 that form
when 1.34 x 103g of oxygen completely reacts
according to the following equation:
4
Cr(s) +
O2(g) →
2
Cr203(s)
х
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
3
4
mol O2
mol Cr
1.34 × 103
1.68 x 1025
g Cr2O3
32.00
3.78 x 1025
mol Cr2O3
2.52 x 1025
152.00
g O2
52.00
g Cr
4.24 x 103
molecules Cr2O3
6.022 x 1023
Tap here or pull up for additional resources
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