How many grams of oxygen gas are produced when 2.43 x 104g of KCIO, are completely reacted according to the following chemical equation: 2 KCIO;(s) - 2 KCI(s) + 3 02(g) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 6.022 x 1023 2 5.95 x 10-6 2.43 x 10-4 1 1.98 x 10-6 3 32.00 9.52 x 10-5 1.90 x 104 74.55 122.55 2.97 x 10-6 g KCI g KCIO, g O2 mol O2 mol KCI mol KCIO,

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Transcription for Educational Website**

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**How many grams of oxygen gas are produced when 2.43 x 10^-4 g of KClO₃ are completely reacted according to the following chemical equation:**

\[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \]

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**Reaction Setup:**

- **Starting Amount**: Initial quantity required for the calculation.
  
\[ \text{( )} \times \left( \frac{\text{( )}}{\text{( )}} \right) \]

---

**Tools and Inputs:**

1. **Add Factor**: 
   - Multiply by: \( \text{( )} \)

2. **Answer**: 
   - Result displayed here: \(-\) 

3. **Reset**: 
   - Button to clear entries: \( \overset{\curvearrowleft}{} \)

---

**Constants and Conversions:**

| Value | Description |
|-------|-------------|
| \(6.022 \times 10^{23}\) | Avogadro's number |
| \(5.95 \times 10^{-6}\) | Molar mass conversion |
| \(2.43 \times 10^{-4}\) | Given mass of KClO₃ |
| \(1\)             | Unit multiplier |
| \(1.98 \times 10^{-6}\) | Conversion factor |
| \(3\)              | Stoichiometric coefficient for O₂ |
| \(32.00\)          | Molar mass of O₂ (g/mol) |
| \(9.52 \times 10^{-5}\) | Conversion factor |
| \(1.90 \times 10^{-4}\) | Conversion factor |
| \(74.55\)          | Molar mass of KCl (g/mol) |
| \(122.55\)         | Molar mass of KClO₃ (g/mol) |
| \(2.97 \times 10^{-6}\) | Conversion factor |

| Unit | Description |
|------|-------------|
| \(\text{g KCl}\) | Grams of potassium chloride |
| \(\text{g KClO}_3\) | Grams of potassium chlorate |
| \(\text{g O}_2
Transcribed Image Text:**Transcription for Educational Website** --- **How many grams of oxygen gas are produced when 2.43 x 10^-4 g of KClO₃ are completely reacted according to the following chemical equation:** \[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \] --- **Reaction Setup:** - **Starting Amount**: Initial quantity required for the calculation. \[ \text{( )} \times \left( \frac{\text{( )}}{\text{( )}} \right) \] --- **Tools and Inputs:** 1. **Add Factor**: - Multiply by: \( \text{( )} \) 2. **Answer**: - Result displayed here: \(-\) 3. **Reset**: - Button to clear entries: \( \overset{\curvearrowleft}{} \) --- **Constants and Conversions:** | Value | Description | |-------|-------------| | \(6.022 \times 10^{23}\) | Avogadro's number | | \(5.95 \times 10^{-6}\) | Molar mass conversion | | \(2.43 \times 10^{-4}\) | Given mass of KClO₃ | | \(1\) | Unit multiplier | | \(1.98 \times 10^{-6}\) | Conversion factor | | \(3\) | Stoichiometric coefficient for O₂ | | \(32.00\) | Molar mass of O₂ (g/mol) | | \(9.52 \times 10^{-5}\) | Conversion factor | | \(1.90 \times 10^{-4}\) | Conversion factor | | \(74.55\) | Molar mass of KCl (g/mol) | | \(122.55\) | Molar mass of KClO₃ (g/mol) | | \(2.97 \times 10^{-6}\) | Conversion factor | | Unit | Description | |------|-------------| | \(\text{g KCl}\) | Grams of potassium chloride | | \(\text{g KClO}_3\) | Grams of potassium chlorate | | \(\text{g O}_2
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