12. Show the initiation, propagation, and termination steps (6 reactions total) for the following reaction: light CH;CH2CH3 + Cl2 CH;CH,CH2CI + HCI
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![12. Show the initiation, propagation, and termination steps (6 reactions total) for the following reaction:
light
CH;CH,CH3 + Cl2
CH;CH2CH;CI + HCI](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6d53ed2-9c89-4ae5-b3a5-84b2602ba4e8%2F2e7a3d50-64d8-43ae-a0e2-9c16a17159c8%2Ffvzn4t_processed.png&w=3840&q=75)
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- didentify the Allowry reactions, as substitution, elimination, or addition DrawWelection arrows to show how the in each reactors Circle and identify any reactive bands break & form intermediates of carbon. Ħ Br Br → AH-Br →→ → XB²C. HINT: Hydrogenation Br + O ? O -Which of the following is a second chain propagation step in the free radical chlorination of ethane? A. Cl· + Cl· + hv → Cl2 B. CH;CH2• + •CI → CH3CH2CI O C. Cl2 → 2Cl· D. CH3CH2• + Cl2 → CH3CH2CI + Cl• O E. CH3CH2 •+ • CH2CH3 CH2CH3 - CH3CH2CH2CH3
- Calculate the ▲H° for each chain propagation step and show that they add up to the observed ▲H° for the overall reaction.The net reaction of the monobromination of cyclopentane is shown below. Draw and label the initiation and propagation steps and one termination step. hv Br2 Br HBrA mechanism for the reaction of bromine with 4,4-dimethylcyclopentene in water is shown below. Which of the following statements about this mechanism is correct? Step 1 Br Br Br + Br Br Step 2 Br ;OH OH2 Br Br XX .. Step 3 + Hо HO:) H. O In Step 1, bromine could add to the other face of the alkene, giving a bromonium ion that is the enantiomer of the one shown. O In Step 2, water could attack the other carbon atom of the bromonium ion, leading to the enantiomer of the product shown. O This mechanism is complete and correct. O In Step 2, water could attack the bromonium ion from the other side, leading to the cis product.
- CH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:Draw the product in the box and show the initiation step, first propagation step, and second propagation step.Identify the products of the 1,2-addition for the following reaction. OI O II O III O IV O III and IV Br Br + En Br Br + En || Br₂ CC14 ? Br Br + En ||| Br + En IV
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