A mechanism for the reaction of bromine with 4,4-dimethylcyclopentene in water is shown below. Which of the following statements about this mechanism is correct? Step 1 Br Br Br + Br Br Step 2 Br OH2 OH2 Br Br OH2 Step 3 + Hо H OH O In Step 1, bromine could add to the other face of the alkene, giving a bromonium ion that is the enantiomer of the one shown. O In Step 2, water could attack the other carbon atom of the bromonium ion, leading to the enantiomer of the product shown. O This mechanism is complete and correct. O In Step 2, water could attack the bromonium ion from the other side, leading to the cis product.
A mechanism for the reaction of bromine with 4,4-dimethylcyclopentene in water is shown below. Which of the following statements about this mechanism is correct? Step 1 Br Br Br + Br Br Step 2 Br OH2 OH2 Br Br OH2 Step 3 + Hо H OH O In Step 1, bromine could add to the other face of the alkene, giving a bromonium ion that is the enantiomer of the one shown. O In Step 2, water could attack the other carbon atom of the bromonium ion, leading to the enantiomer of the product shown. O This mechanism is complete and correct. O In Step 2, water could attack the bromonium ion from the other side, leading to the cis product.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Mechanism for the Reaction of Bromine with 4,4-Dimethylcyclopentene in Water**
The mechanism involves the addition of bromine to 4,4-dimethylcyclopentene, resulting in different potential products depending on how bromine and water interact with the substrate. Below is a detailed description of the steps and a multiple-choice question related to the correctness of the mechanism.
**Step 1:**
- The reaction begins with the attack of the double bond in 4,4-dimethylcyclopentene on a bromine molecule (Br₂).
- This results in the formation of a cyclic bromonium ion and the release of a bromide ion (Br⁻).
- The bromonium ion has a positive charge localized on the bromine atom.
**Step 2:**
- Water (H₂O) approaches and attacks the more substituted carbon atom of the bromonium ion, opening the three-membered ring.
- This reaction forms an intermediate with a hydroxyl group (OH) attached and a positively charged oxygen atom.
**Step 3:**
- A proton transfer occurs from the oxygen to a water molecule, resulting in the formation of a neutral alcohol and hydronium ion (H₃O⁺).
**Graph/Diagram Explanation:**
- The diagram shows the transformation from 4,4-dimethylcyclopentene to a bromonium ion, then to the intermediate, and finally to the end product, a bromohydrin, along with the generation of H₃O⁺.
**Multiple-choice question:**
- Which of the following statements about this mechanism is correct?
- In Step 1, bromine could add to the other face of the alkene, giving a bromonium ion that is the enantiomer of the one shown.
- In Step 2, water could attack the other carbon atom of the bromonium ion, leading to the enantiomer of the product shown.
- This mechanism is complete and correct.
- In Step 2, water could attack the bromonium ion from the other side, leading to the cis product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6c5565a-787b-43d3-b23e-780453faf6da%2Fa80416bb-bac5-42cf-b93a-b2a23b01af79%2F3wwnmcn_processed.png&w=3840&q=75)
Transcribed Image Text:**Mechanism for the Reaction of Bromine with 4,4-Dimethylcyclopentene in Water**
The mechanism involves the addition of bromine to 4,4-dimethylcyclopentene, resulting in different potential products depending on how bromine and water interact with the substrate. Below is a detailed description of the steps and a multiple-choice question related to the correctness of the mechanism.
**Step 1:**
- The reaction begins with the attack of the double bond in 4,4-dimethylcyclopentene on a bromine molecule (Br₂).
- This results in the formation of a cyclic bromonium ion and the release of a bromide ion (Br⁻).
- The bromonium ion has a positive charge localized on the bromine atom.
**Step 2:**
- Water (H₂O) approaches and attacks the more substituted carbon atom of the bromonium ion, opening the three-membered ring.
- This reaction forms an intermediate with a hydroxyl group (OH) attached and a positively charged oxygen atom.
**Step 3:**
- A proton transfer occurs from the oxygen to a water molecule, resulting in the formation of a neutral alcohol and hydronium ion (H₃O⁺).
**Graph/Diagram Explanation:**
- The diagram shows the transformation from 4,4-dimethylcyclopentene to a bromonium ion, then to the intermediate, and finally to the end product, a bromohydrin, along with the generation of H₃O⁺.
**Multiple-choice question:**
- Which of the following statements about this mechanism is correct?
- In Step 1, bromine could add to the other face of the alkene, giving a bromonium ion that is the enantiomer of the one shown.
- In Step 2, water could attack the other carbon atom of the bromonium ion, leading to the enantiomer of the product shown.
- This mechanism is complete and correct.
- In Step 2, water could attack the bromonium ion from the other side, leading to the cis product.
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