12. A proton in the solar wind travels perpendicularly at 3.00x10° m/s across the Earth's magnetic field lines. The field at that location is 0.0000100 T. a. Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 10-19 N) b. Since this force acts at right angles to its velocity, the proton will experience this as a

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter22: Magnetic Forces And Magnetic Fields
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12. A proton in the solar wind travels perpendicularly at 3.00×10 m/s across the Earth's magnetic field
lines. The field at that location is 0.0000100 T.
a. Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 10-1º N)
b. Since this force acts at right angles to its velocity, the proton will experience this as a
centripetal force, causing the proton to have a "corkscrew" circular motion. Calculate the
radius of these circles as the proton travels through the field. (ans: 313 m)
2020-12-11
Page 10 of 17
Transcribed Image Text:12. A proton in the solar wind travels perpendicularly at 3.00×10 m/s across the Earth's magnetic field lines. The field at that location is 0.0000100 T. a. Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 10-1º N) b. Since this force acts at right angles to its velocity, the proton will experience this as a centripetal force, causing the proton to have a "corkscrew" circular motion. Calculate the radius of these circles as the proton travels through the field. (ans: 313 m) 2020-12-11 Page 10 of 17
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