12. A cylindrical steel bar (1045 steel) is subjected to repeated tension-compression stress cycling along its axis. If the load amplitude is 20 kN, calculate the minimum allowable bar radius to avoid fatigue failure. Use a safety factor of 2.5 and use the below figure for the fatigue limit stress. Round answer to two significant figures. Stress amplitude, S (MPa) 500 400 300 200 100 10³ 104 105 1045 steel 2014-T6 aluminum alloy Red brass 10 107 10" Cycles to failure, N 10 T 70 60 50 40 30 20 10 0 1010 Stress amplitude (10 psi)

12. A cylindrical steel bar (1045 steel) is subjected to repeated tension-compression stress cycling along its axis. If the load amplitude is 20 kN, calculate the minimum allowable bar radius to avoid fatigue failure. Use a safety factor of 2.5 and use the below figure for the fatigue limit stress. Round answer to two significant figures. Stress amplitude, S (MPa) 500 400 300 200 100 10³ 104 105 1045 steel 2014-T6 aluminum alloy Red brass 10 107 10" Cycles to failure, N 10 T 70 60 50 40 30 20 10 0 1010 Stress amplitude (10 psi)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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21 A simply supported beam of circular cross- section made up of hot rolled steel is subjected to a fluctuating load that varies from -F to +3F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 82 N/mm2 to -36 N/mm2. Assume the following values: Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design, i) Calculate the mean stress in N/mm2 and variable stress in N/mm² ii) Calculate the Ultimate Strength in N/mm2 iii) Calculate the endurance strength in N/mm2
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I need neat Handwritten Solution. Answer: 1.07
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Sy=370 MPa
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