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1:19 PM | 0.1KB/s "" 2 bartleby.com/questior Homework help starts here! given : 4G Vo LTE Vo LTE 91 [17] ASK AN EXPERT VX MATH SOLVER = 0 -0.101sin(4.95t) + 0.3cos (4.95t) (a): when =0°, from the given equation 0 -0.101sin(4.95t) + 0.3cos (4.95t) 0.101sin(4.95t) = 0.3cos(4.95t) tan (4.95t) 0.3 = 0.101 4.95t = tan¹(0.11) t = 0.2517s Now Angular velocity, w * w = 0 = (−0.101 × 4.95) cos(4.95t) - (0.3 * 4.95) sin(4.95t) w = -1.57 (-ve sign shows direction is clock wise) so velocity is v = w* L = (-1.57) * 0.4 since sine = -0.626m/s Angular acceleration, απ 9.81 sin(0)⇒(a = 0) Acceleration a aL 0 0.4 a = 0 Velocity, v=-0.626m/s Acceleration a = 0

1:19 PM | 0.1KB/s "" 2 bartleby.com/questior Homework help starts here! given : 4G Vo LTE Vo LTE 91 [17] ASK AN EXPERT VX MATH SOLVER = 0 -0.101sin(4.95t) + 0.3cos (4.95t) (a): when =0°, from the given equation 0 -0.101sin(4.95t) + 0.3cos (4.95t) 0.101sin(4.95t) = 0.3cos(4.95t) tan (4.95t) 0.3 = 0.101 4.95t = tan¹(0.11) t = 0.2517s Now Angular velocity, w * w = 0 = (−0.101 × 4.95) cos(4.95t) - (0.3 * 4.95) sin(4.95t) w = -1.57 (-ve sign shows direction is clock wise) so velocity is v = w* L = (-1.57) * 0.4 since sine = -0.626m/s Angular acceleration, απ 9.81 sin(0)⇒(a = 0) Acceleration a aL 0 0.4 a = 0 Velocity, v=-0.626m/s Acceleration a = 0

Understanding Business
Understanding Business
12th Edition
ISBN:9781259929434
Author:William Nickels
Publisher:William Nickels
Chapter1: Taking Risks And Making Profits Within The Dynamic Business Environment
Section: Chapter Questions
Problem 1CE
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1:19 PM | 0.1KB/s "" 2 bartleby.com/questior Homework help starts here! given : 4G Vo LTE Vo LTE 91 [17] ASK AN EXPERT VX MATH SOLVER = 0 -0.101sin(4.95t) + 0.3cos (4.95t) (a): when =0°, from the given equation 0 -0.101sin(4.95t) + 0.3cos (4.95t) 0.101sin(4.95t) = 0.3cos(4.95t) tan (4.95t) 0.3 = 0.101 4.95t = tan¹(0.11) t = 0.2517s Now Angular velocity, w * w = 0 = (−0.101 × 4.95) cos(4.95t) - (0.3 * 4.95) sin(4.95t) w = -1.57 (-ve sign shows direction is clock wise) so velocity is v = w* L = (-1.57) * 0.4 since sine = -0.626m/s Angular acceleration, απ 9.81 sin(0)⇒(a = 0) Acceleration a aL 0 0.4 a = 0 Velocity, v=-0.626m/s Acceleration a = 0
Transcribed Image Text:1:19 PM | 0.1KB/s "" 2 bartleby.com/questior Homework help starts here! given : 4G Vo LTE Vo LTE 91 [17] ASK AN EXPERT VX MATH SOLVER = 0 -0.101sin(4.95t) + 0.3cos (4.95t) (a): when =0°, from the given equation 0 -0.101sin(4.95t) + 0.3cos (4.95t) 0.101sin(4.95t) = 0.3cos(4.95t) tan (4.95t) 0.3 = 0.101 4.95t = tan¹(0.11) t = 0.2517s Now Angular velocity, w * w = 0 = (−0.101 × 4.95) cos(4.95t) - (0.3 * 4.95) sin(4.95t) w = -1.57 (-ve sign shows direction is clock wise) so velocity is v = w* L = (-1.57) * 0.4 since sine = -0.626m/s Angular acceleration, απ 9.81 sin(0)⇒(a = 0) Acceleration a aL 0 0.4 a = 0 Velocity, v=-0.626m/s Acceleration a = 0
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