11. At a carnival, a dodgem car (with two heavy occupants) of mass 220 kg, collides head-on with another car (with two lighter occupants) of mass 160 kg. Before the collision the heavier car is travelling 2 ms-1, while the lighter one is travelling at 3 ms-1 in the opposite direction. After the collision the heavy car moves backwards along its original path at 1 ms-1. (a) What is the velocity of the lighter car after the collision?
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- An pickup truck with mass 1.85 103 kg is traveling eastbound at +14.7 m/s, while a compact car with mass 8.55 102 kg is traveling westbound at -14.7 m/s. (See figure.) The vehicles collide head-on, becoming entangled. (a) Find the speed of the entangled vehicles after the collision. (b) Find the change in the velocity of each vehicle. Δvtruck= ? m/s Δvcar= ? m/sA mass of m1= 4 kg moving with a velocity of v1=(2 m/s)ˆi (positive x−direction) collides with another mass, m2 moving at v2= (−4 m/s)ˆi (negative x−direction). The masses collide and stick together, moving off with a velocity of v= (−2 m/s)ˆi. What is m2? A)m2= 4 kg B)m2= 8 kg C)m2= 12 kg D)m2= 16 kgSuppose M1 (1 kg) is moving at 3 m/s in the + x direction. M2 (2 kg) is moving at 3 m/s in the -x direction. If they collide and stick together, what will be their final velocity (in m/s)?
- 2 - A bullet of mass, m = 8x10-³ kg moving horizontally with a speed vo strikes a wood block of mass M = 0.4 kg initially at rest. Just after the collision, the bullet passes through the block and goes out along the initial direction with a speed v = 0.20x10³ m/s, and the wood block moves with V = 5 m/s, see the figure. (a) Find the velocity of the bullet (vo) before the collision. What is the impulse induced on the block during this collision? (b) After the collision the wood block moves, d = 2 m on the horizontal table before it stops, find the friction force acting on the wood block. m vo mCarry Collision Insurance! A 1,906 kg car stopped at a traffic light is struck from the rear by a 953-kg car. The two cars become entangled, moving along the same path as that of the originally moving car. If the smaller car were moving 26.7 m/s before the collision, what is the velocity of the entangled cars after the collision? (Assume the smaller car initially moves in the positive direction.) SOLUTION Conceptualize This kind of collision is easily visualized, and one can predict that after the collision both cars will be moving in the same direction as that of the initially moving car. Because the initially moving car has only half the mass of the stationary car, we expect the final velocity of the cars to be relatively Categorize We identify the two cars as an isolated system in terms of momentum in the horizontal direction and apply the impulse approximation during the short time interval of the collision. The phrase "become entangled" tells us to categorize the collision as…A car, with a mass of 1240 kg, is moving towards an intersection at a velocity of 26.6 m/s towards the South. At the intersection, it collides with a truck that has a mass of 1580 kg and is moving with a velocity of 14.0 m/s towards the West. When they collide, the two vehicles stick together. 15. The magnitude of the final velocity for the car and truck is Answer to 3 significant digits. m/s. (Record your answer in the numerical-response section below.) Your answer:
- A car of mass 2900 kg collides with a truck of mass 4400 kg, and just after the collision the car and truck slide along, stuck together. The car's velocity just before the collision was < 39, 0, 0> m/s, and the truck's velocity just before the collision was < -17, 0, 15> m/s.(a) What is the velocity of the stuck-together car and truck just after the collision?A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, moving south at 4.20 m/s; and mass 7.00 kg, moving north at 2.00 m/s. What is the total momentum of the system? Take north as the positive axis. Enter a positive answer if the total momentum is due north and a negative answer if the total momentum is due south. ____kg ⋅ m/s.
- A block of mass 1.57 kg is placed on a frictionless floor and initially pushed northward, where upon it begins sliding with a constant speed of 5.16 m/s. It eventually collides with a second, stationary block, of mass 3.01 kg, head-on, and rebounds back to the south. The collision is 100% elastic. What will be the speeds of the 1.57-kg and 3.01-kg blocks, respectively, after this collision? 1.62 m/s and 3.54 m/s 3.54 m/s and 1.62 m/s 2.06 m/s and 2.58 m/s 0.65 m/s and 2.10 m/sA steel ball of mass 300.0 g moving with a velocity of 2.25 m/s [E], strikes a second ball of mass 0.20 kg. initially atrest. The collision is glancing one, causing the moving ball to have a velocity of 1.75 m/s [ E30N] after the collision.Draw a detailed diagram of before and after collision. Determine the velocity (mag & direction) of the second ball.2) Mass 1 = 5 kg is initially travelling east at 4.5 m/s. It strikes a stationary Mass 2 = 2.5 kg, sending it recoiling at a velocity = 5.2 m/s in the direction 30° S of E. a) Find the magnitude and direction of the final velocity for mass 1. b) What kind of collision is this?