39. An explosion breaks a 33.0-kg object into three parts. The object is initially moving at a velocity of 28.0 m/s duesouth. Part (1) has a mass m₁ = 4.60-kg and a velocity of 55.0 m/s due east. Part (2) has a mass m₂ = 5.00-kg and avelocity of 77.0 m/s due north. Find the direction of the velocity of part (3).o south of west80$4888ETDECRF%5VTGMacBook Air6:BFOY&H744N8J19MDDKMOSISOVH1P-61.commandoption

Name: 39. An explosion breaks a 33.0-kg object into three parts. The object
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Description: 39. An explosion breaks a 33.0-kg object into three parts. The object is initially moving at a velocity of 28.0 m/s duesouth. Part (1) has a mass m₁ = 4.60-kg and a velocity of 55.0 m/s due east. Part (2) has a mass m₂ = 5.00-kg and avelocity of 77.

Answered: 9. An explosion breaks a 33.0-kg object…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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9. An explosion breaks a 33.0-kg object into three parts. The object is initially moving at a velocity of 28.0 m/s due
south. Part (1) has a mass m₁ = 4.60-kg and a velocity of 55.0 m/s due east. Part (2) has a mass m₂ = 5.00-kg and a
velocity of 77.0 m/s due north. Find the direction of the velocity of part (3).
o south of west
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Expert Solution

Step 1

The following problem involves the law of conservation of momentum. The law gives the relation:

Initial momentum = Final momentum

Given, Initial mass, M = 33 kg

Initial velocity, u = 28 m/s

m₁ = 4.60 kg

v₁ = 55 m/s

m₂ = 5.00 kg

v₂ = 77 m/s

Here, we take the East as +x direction and North as +y direction.

Mass of remaining part, m₃ = 33-(4.60+5.00) = 23.4 kg

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