4. Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of ma 17.5 kg and an initial velocity of VOA = 8.10 m/s, due east. Object B, however, has a mass of må 30.0 kg 4.85 m/s, due north. Find the magnitude of and an initial velocity of VOB the final velocity of the two-object system after the collision. m/s = = =

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### Physics Problem: Completely Inelastic Collision

**Problem Statement:**

Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved.

- **Object A:**
  - Mass (\(m_A\)): 17.5 kg
  - Initial Velocity (\(v_{0A}\)): 8.10 m/s (due east)

- **Object B:**
  - Mass (\(m_B\)): 30.0 kg
  - Initial Velocity (\(v_{0B}\)): 4.85 m/s (due north)

**Task:** Find the magnitude of the final velocity of the two-object system after the collision.

**Solution:**

To find the final velocity of the combined system, we will use the principle of conservation of momentum and vector addition:

1. **Calculate Initial Momenta:**
   - Momentum of Object A (\(p_A\)) = \( m_A \times v_{0A} \)
   - Momentum of Object B (\(p_B\)) = \( m_B \times v_{0B} \)

2. **Determine Final Velocity Components:**
    - Total mass of the system (\(m_{total}\)) = \( m_A + m_B \)
    - Use conservation of momentum in each direction (east and north) to calculate the velocity components of the combined system.

3. **Find Magnitude of Final Velocity:**
    - Combine the velocity components using the Pythagorean theorem.

**Graphical Representation:**

There are no graphs or diagrams provided. However, you can imagine a coordinate system where:
- The x-axis represents the east direction.
- The y-axis represents the north direction.

The initial momentum vectors would be represented along these axes and after collision, the resultant momentum vector (and hence the final velocity vector) can be found using vector addition.

**Please input your calculated final velocity below:**

\[ \boxed{\hspace{3cm}} \text{m/s} \]

This problem reinforces the understanding of inelastic collisions and the conservation of momentum in two dimensions.
Transcribed Image Text:### Physics Problem: Completely Inelastic Collision **Problem Statement:** Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. - **Object A:** - Mass (\(m_A\)): 17.5 kg - Initial Velocity (\(v_{0A}\)): 8.10 m/s (due east) - **Object B:** - Mass (\(m_B\)): 30.0 kg - Initial Velocity (\(v_{0B}\)): 4.85 m/s (due north) **Task:** Find the magnitude of the final velocity of the two-object system after the collision. **Solution:** To find the final velocity of the combined system, we will use the principle of conservation of momentum and vector addition: 1. **Calculate Initial Momenta:** - Momentum of Object A (\(p_A\)) = \( m_A \times v_{0A} \) - Momentum of Object B (\(p_B\)) = \( m_B \times v_{0B} \) 2. **Determine Final Velocity Components:** - Total mass of the system (\(m_{total}\)) = \( m_A + m_B \) - Use conservation of momentum in each direction (east and north) to calculate the velocity components of the combined system. 3. **Find Magnitude of Final Velocity:** - Combine the velocity components using the Pythagorean theorem. **Graphical Representation:** There are no graphs or diagrams provided. However, you can imagine a coordinate system where: - The x-axis represents the east direction. - The y-axis represents the north direction. The initial momentum vectors would be represented along these axes and after collision, the resultant momentum vector (and hence the final velocity vector) can be found using vector addition. **Please input your calculated final velocity below:** \[ \boxed{\hspace{3cm}} \text{m/s} \] This problem reinforces the understanding of inelastic collisions and the conservation of momentum in two dimensions.
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