Carry Collision Insurance!A 1,906 kg car stopped at a traffic light is struck from the rear by a 953-kg car. The two cars become entangled, moving along the same path as that of the originally moving car. If the smaller car were moving26.7 m/s before the collision, what is the velocity of the entangled cars after the collision? (Assume the smaller car initially moves in the positive direction.)SOLUTIONConceptualize This kind of collision is easily visualized, and one can predict that after the collision both cars will be moving in the same direction as that of the initially moving car. Because the initially moving car has only half the mass of the stationary car, we expect the final velocity of the cars to be relativelyCategorize We identify the two cars as an isolated system in terms of momentum in the horizontal direction and apply the impulse approximation during the short time interval of the collision. The phrase "become entangled" tells us to categorize the collision as perfectlyAnalyze The magnitude of the total momentum of the system before the collision is equal to that of thecar because the larger car is initially at rest. (Use the following as necessary: m,, m2, and vVp)Use the isolated system model for momentum:Ap - 0-P, - P,m,v -(Solve for v, (in m/s) and substitute numerical values (Indicate the direction with the sign of your answer.):m,v,m/sm, + m,Finalize Because the final velocity is positive, the direction of the final velocity of the combination isthe velocity of the initially moving car as predicted. The speed of the combination is also much lower than the initial speed of the moving car.EXERCISEHint(a) What is the loss of kinetic energy (K, - K, in kJ) in the situation described in the Example?Use momentum and energy methods to find the final velocities and, from them, calculate the change in kinetic energy. kJ(b) What if the 953 kg car actually moves backwards with a speed of 1.6 m/s right after the collision instead of having a perfectly inelastic collision? What is the velocity of the heavier car (in m/s) immediately after the collision? Use the same convention for positive direction as defined in the Example. (Indicate the direction with the sign of your answer.)Use momentum and energy methods to find the final velocities. m/s(c) What is the loss of kinetic energy (in kJ) in this case?Use the initial and the final velocitiescalculate the change in kinetic energy. kJNeed Help? Read ItSubmit Answer

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Collision Insurance! 6 kg car stopped at a traffic light is struck from the rear by a 953-kg car. The two cars become entangled, moving along the same path as that of the originally moving car. If the smaller car were moving at 26.7 mys before the collision, what is the velocity of the entangled cars after the collision? (Assume the smaller car initially moves in the positive direction.) TION ptualize This kind of colision is easily visualized, and one can predict that after the collision both cars will be moving in the same direction as that of the initially moving car. Because the initially moving car has only haif the mass of the stationary car, we expect the final velocity of the cars to be relatively V orize We identify the two ca rs as an isolated system in terms of momentum in the horizontal direction and apply the impulse approximation during the short time interval of the collision. The phrase "become entangled" tells us to categorize the colision as perfectly e The magnitude of the total momentum of the system before the collision is equal to that of the car because the larger car is intially at rest. (Use the following as necessary: m, my and ve) isolated system model for momentum: or v, (in m/s) and substitute numerical values (Indicate the direction with the sign of your answer.): m/s e Because the final velocity is positive, the direction of the final velocity of the combination is V the velocity of the initially moving car as predicted. The speed of the combination is also much lower than the initial speed of the moving car. Int What is the loss of kinetic energy (K, - K. in k) in the situation described in the Example? se momentum and energy methods to find the final velocities and, from them, caloulate the change in kinetic energy. k What if the 953 kg car actually moves backwards with a speed of 1.6 m/s right after the collision instead of having a perfectly inelastic collision? What is the velocity of the heavier car (in m/s) immediately after the collision? Use the same convention for positive direction as defined in the Example. (Indicate the direction with the sign of your answer.) use momentum and energy methods to find the final velocities. m/s What is the loss of kinetic energy (in k) in this case? Use the initial and the final velocities to caiculate the change in kinetic energy. k Help?

Collision Insurance! 6 kg car stopped at a traffic light is struck from the rear by a 953-kg car. The two cars become entangled, moving along the same path as that of the originally moving car. If the smaller car were moving at 26.7 mys before the collision, what is the velocity of the entangled cars after the collision? (Assume the smaller car initially moves in the positive direction.) TION ptualize This kind of colision is easily visualized, and one can predict that after the collision both cars will be moving in the same direction as that of the initially moving car. Because the initially moving car has only haif the mass of the stationary car, we expect the final velocity of the cars to be relatively V orize We identify the two ca rs as an isolated system in terms of momentum in the horizontal direction and apply the impulse approximation during the short time interval of the collision. The phrase "become entangled" tells us to categorize the colision as perfectly e The magnitude of the total momentum of the system before the collision is equal to that of the car because the larger car is intially at rest. (Use the following as necessary: m, my and ve) isolated system model for momentum: or v, (in m/s) and substitute numerical values (Indicate the direction with the sign of your answer.): m/s e Because the final velocity is positive, the direction of the final velocity of the combination is V the velocity of the initially moving car as predicted. The speed of the combination is also much lower than the initial speed of the moving car. Int What is the loss of kinetic energy (K, - K. in k) in the situation described in the Example? se momentum and energy methods to find the final velocities and, from them, caloulate the change in kinetic energy. k What if the 953 kg car actually moves backwards with a speed of 1.6 m/s right after the collision instead of having a perfectly inelastic collision? What is the velocity of the heavier car (in m/s) immediately after the collision? Use the same convention for positive direction as defined in the Example. (Indicate the direction with the sign of your answer.) use momentum and energy methods to find the final velocities. m/s What is the loss of kinetic energy (in k) in this case? Use the initial and the final velocities to caiculate the change in kinetic energy. k Help?