Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
11- Let G = 4xa, +2zay+2ya,. Given an initial point P (2, 1, 1) and a final point Q(4, 3, 1), find f G.dL using the path: a) straight line: y = x-1, z = 1; b) parabola: 6y=x²+2, z = 1: With Gas given, the line integral will be [G-AL = [~ 4x dx + [* 2zdy + [* 2y dz G. dL 2ydz Clearly, we are going nowhere in z, so the last integral is zero. With z = 1, the first two evaluate as √ G. dL = 2x² + 2y|₁ = 28 The paths specified in parts a and b did not play a role, meaning that the integral between the specified points is path-independent.

11- Let G = 4xa, +2zay+2ya,. Given an initial point P (2, 1, 1) and a final point Q(4, 3, 1), find f G.dL using the path: a) straight line: y = x-1, z = 1; b) parabola: 6y=x²+2, z = 1: With Gas given, the line integral will be [G-AL = [~ 4x dx + [* 2zdy + [* 2y dz G. dL 2ydz Clearly, we are going nowhere in z, so the last integral is zero. With z = 1, the first two evaluate as √ G. dL = 2x² + 2y|₁ = 28 The paths specified in parts a and b did not play a role, meaning that the integral between the specified points is path-independent.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
(Electromagnetic field)I want a detailed solution for this solution
Electromagnetic field)I want a detailed solution for this solution 11- Let G = 4xa, +2zay+2ya₂. Given an initial point P (2, 1, 1) and a final point Q(4, 3, 1), find f G-dL using the path: a) straight line: y = x-1, z = 1; b) parabola: 6y=x²+2, z = 1: With G as given, the line integral will be [G.dl. = [*Axdx + f2zdy + f zydz dL 4x Clearly, we are going nowhere in z, so the last integral is zero. With z = 1, the first two evaluate as √ G. dL = 2x² | 2 + 2y|²³ ² 12- The paths specified in parts a and b did not play a role, meaning that the integral between the specified points is path-independent. Three point charges, 0.4 µC each, are located at (0, 0, -1), (0, 0, 0), and (0, 0, 1), in free space. a) Find an expression for the absolute potential as a function of z along the line x = 0, y = 1: From a point located at position z along the given line, the distances to the three charges are R₁ = √√(z − 1)² + 1, R2 : 2 = √√₂² + 1, and R3 = √√(z + 1)² + 1. The total potential will be V(z) Using q = 4 x 10-7 C, this becomes V(z) = (3.6 × 10³) = = 28 9 1 1 1 + + 4л€0 R₁ R₂ R3 1 √(2−1)²+1 + 1 1 √2+1 √√2² +1 √(z+1)² + + V
Transcribed Image Text:Electromagnetic field)I want a detailed solution for this solution 11- Let G = 4xa, +2zay+2ya₂. Given an initial point P (2, 1, 1) and a final point Q(4, 3, 1), find f G-dL using the path: a) straight line: y = x-1, z = 1; b) parabola: 6y=x²+2, z = 1: With G as given, the line integral will be [G.dl. = [*Axdx + f2zdy + f zydz dL 4x Clearly, we are going nowhere in z, so the last integral is zero. With z = 1, the first two evaluate as √ G. dL = 2x² | 2 + 2y|²³ ² 12- The paths specified in parts a and b did not play a role, meaning that the integral between the specified points is path-independent. Three point charges, 0.4 µC each, are located at (0, 0, -1), (0, 0, 0), and (0, 0, 1), in free space. a) Find an expression for the absolute potential as a function of z along the line x = 0, y = 1: From a point located at position z along the given line, the distances to the three charges are R₁ = √√(z − 1)² + 1, R2 : 2 = √√₂² + 1, and R3 = √√(z + 1)² + 1. The total potential will be V(z) Using q = 4 x 10-7 C, this becomes V(z) = (3.6 × 10³) = = 28 9 1 1 1 + + 4л€0 R₁ R₂ R3 1 √(2−1)²+1 + 1 1 √2+1 √√2² +1 √(z+1)² + + V
Expert Solution
steps

Step by step

Solved in 4 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS