11) In a survey of 1383 U.S. adults, 1079 favor increasing federal funding for research on wind, solar, and hydrogen technology. (Adapted from Pew Research Center) (a) Construct a 90% confidence interval for the population proportion of adults who favor increased funding. (b) Find the minimum sample size needed to estimate this population proportion at the 90% confidence level in order to ensure that the estimate is accurate within 4% of the population proportion.
Q: In a survey of 800 US adults, 90 are making the minimum payment(s) on their credit card(s).…
A: Solution: Given information: n= 800 Sample size of adults x= 90 adults are making the minimum…
Q: A study of 420,019 cell phone users found that 140 of them developed cancer of the brain or nervous…
A: Given, Favorable Cases XX = 140140 Sample Size NN = 420019420019 To find, construct a…
Q: A poll of 827 students at Alpha State College found that 61% of those polled preferred a quarter…
A: Given that Sample size n = 827 Sample proportion of students who prefer a quarter system = 0.61 The…
Q: A study of 420,082 cell phone users found that 135 of them developed cancer of the brain or nervous…
A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…
Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 439 green peas…
A:
Q: The National Health and Nutrition Examination Survey is conducted each year and contains a variety…
A: There are two independent samples which are year 2003 and year 2018. Both samples come from…
Q: 3) A corporation employs 148 sales representatives. A random sample of 60 of them was taken, and it…
A: The sample proportion is computed as follows,
Q: Assume that 66 % of single women and 81.9 % of single men own cars. Also assume that these estimates…
A: Given data, p1=66%=0.66 n1=1640 p2=81.9%=0.819 n2=1800 z-value at 99% confidence is Zc=2.576
Q: 2b) The newly approved benefit package for Canada's Women National Football Team is estimated to be…
A: The question is about confidence interval.Given :Range of benefit package for country " C " women…
Q: A survey selected 83 children aged 2-12 from the village of El Abrid, Ethiopia to measure the…
A: Total 83 children : Prevalence for : 13% confidence interval = 5% 95% confidence interval = 21%…
Q: 3. Consider a study in which 2205 adolescents age 12 to 19 took a cardiovascular treadmill test. The…
A: Given that Sample size n =2205 Favorable cases x =750 Sample proportion p^=x/n =750/2205 =0.3401
Q: *** a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell…
A: A study of 420,041 cell phone users found that 0.0314% of them developed cancer of the brain or…
Q: 8. In a survey of a simple random sample of students at a certain college, the sample mean time per…
A: Here we need to find whether the given statement is true or false. We need estimate the sample mean…
Q: a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell…
A: Given that Sample size n = 420078 Number of cell phone user who developed cancer, X = 130 The…
Q: 1. Out of 1,500 licensed drivers, 900 admitted that they do not like to drive at night. What is the…
A: *As per company guidelines, we are supposed to only answer 3 subparts. For next parts kindly…
Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…
A: It is given that the proportion of the students who preferred a quarter system to a trimester…
Q: A study of 420,072 cell phone users found that 130 of them developed cancer of the brain or nervous…
A: The 90% confidence interval can be calculated as:
Q: deprivation by the Centers for Disease Control and Prevention, the proportion of California…
A:
Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 449 green peas…
A: Given that - A genetic experiment with peas resulted in one sample of offspring that consisted of…
Q: ind a 95% confidence interval for the difference between the two proportions. b) Is there a…
A: Let p1 and p2 be the two population proportions of people who said that it is serious.Given…
Q: 4. Assume that 66 % of single women and 81.9% of single men own cars. Also assume that these…
A: From the provided information,
Q: A study of 420,098 cell phone users found that 0.0324% of them developed cancer of the brain or…
A: sample size(n)=420098sample proportion()=0.0324%=0.000324
Q: random samples of 11,559 California and 4,685 Oregon residents. Calculate a 95% confidence interval…
A: See the hand writing solution
Q: A study of 420,078 cell phone users found that 132 of them developed cancer of the brain or nervous…
A: given that,possible chances (x)=132size(n)=420078success rate ( p )= x/n = 0.000314point of estimate…
Q: A study of 420,010 cell phone users found that 132 of them developed cancer of the brain or nervous…
A: Given,n=420010x=132p^=xnp^=132420010=0.000311-p^=1-0.00031=0.99969α=1-0.90=0.1α2=0.05Z0.05 =1.645…
Q: na survey of 2,300 website users, 1,861 cited "seeing photos or videos" as a major reason why they…
A: Given sample size(n)=2300 confidence interval=95%
Q: You are working as an assistant to the dean of institutional research at your university. The dean…
A: Here mean is not given and standard deviation is also not given.
Q: A study of 420,010 cell phone users found that 0.0319% of them developed cancer of the brain or…
A: Solution: Given information: n= 420010 Sample size p^=0.0319100= 0.000319 Sample Proportion
Q: 1. In a sample of 1,000 households in a war-torn country 940 have 0 violent deaths, 50 have 1…
A:
Q: The Harvard School of Public Health conducted a survey of 2770 adults in the United States to…
A: It is given that the sample of adults, n is 2,770, the proportion of Americans who own guns is 26%…
Q: et: Confidence Intervals for Proportions 1. The paralyzed Veterans of America is a philanthropic…
A: Given : n=100000 x=4781 c=95%=0.95
Q: You are working as an assistant to the dean of institutional research at your university. The dean…
A: The question is about confidence interval Given : Randomly selected no. of graduates ( n ) = 100…
Q: 5. At Community Hospital, the burn center is experimenting with a new plasma compress treatment. A…
A: It is given that For sample 1: Favourable cases, X1 = 259 Sample size, n1 = 316 For sample 2:…
Q: 7. A recent survey of 500 women indicated that 29% of women over age 55 in the study were widows.…
A: Givensample size(n)=500p^=29%=0.29confidence level=90%
Q: A Gallup poll of 1015 randomly selected adults found that 69% would oppose a law that limited the…
A: In question, Given that A Gallup poll of 1015 randomly selected adults found that 69% would oppose a…
Q: A study of 420,007 cell phone users found that 136 of them developed cancer of the brain or…
A: Given, n = 420007 X = 136 p^ = Xn = 136420007 = 0.000324 Confidence level = 0.90 To find, a. 90%…
Q: A high school is running a campaign against the over-use of technology in teens. The committee…
A: sample size(n1)=200sample proportion()=0.85sample size(n2)=180sample proportion()=0.55confidence…
Q: A study of 420,098 cell phone users found that 0.0324% of them developed cancer of the brain or…
A: The question is about confidence interval.Given :Sample no. of cell phone users ( n ) = 420098Sample…
Q: study of 420,077 cell phone users found that 133 of them developed cancer of the brain or nervous…
A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…
11) In a survey of 1383 U.S. adults, 1079 favor increasing federal funding for research on wind, solar, and hydrogen technology. (Adapted from Pew Research Center)
(a) Construct a 90% confidence interval for the population proportion of adults who favor increased funding.
(b) Find the minimum
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
- 2. The Vice-Chancellor of a university is concerned that illicit drug use on campus is higher than the 5% acceptable level. A random sample of 140 students revealed that 5 of them had used illicit drug during the last 12 months. Construct a 90% confidence interval to estimate the true proportion of students who use illicit drug. Should the Vice-Chancellor be concerned?9. A study of 420,082 cell phone users found that 140 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0243% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %In a sample of 95 recommendations, it is found that 56% of them made money. Determine the upper bound of the 95% confidence interval for the proportion of recommendations that make money?A study of 420,048 cell phone users found that 137 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0256% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. enter your response here%<p<enter your response here% (Round to three decimal places as needed.) b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not? A. No, because 0.0256% is included in the confidence interval. B. Yes, because 0.0256% is included in the confidence interval. C. Yes, because 0.0256% is not included in the confidence interval. D. No, because 0.0256% is not…A) What proportion of commercial airline pilots are more than 40 years of age? Suppose an analyst has access to a list of all pilots who are members of the Air Line Pilots Association. If this list is used as a frame for the study, she can randomly select a sample of pilots, contact them, and ascertain their ages. From 89 of these pilots so selected, she learns that 48 are more than 40 years of age. Construct an 85% confidence interval to estimate the population proportion of commercial airline pilots who are more than 40 years of age. B) Suppose you want to estimate the proportion of cars that are sport utility vehicles (SUVs) being driven in Regina at rush hour by standing on the corner of Victoria Avenue and Albert Street and counting SUVs. You believe the figure is no higher than 0.40. If you want the error of the confidence interval to be no greater than 0.03, how many cars should you randomly sample? Use a 90% level of confidence.A genetic experiment with peas resulted in one sample of offspring that consisted of 427 green peas and 158 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?Credit card ownership varies across age groups. Suppose that the estimated percentage of people who own at least one credit card is 64% in the 18–24 age group, 84% in the 25–34 age group, 75% in the 35–49 age group, and 77% in the 50+ age group. Suppose these estimates are based on 465 randomly selected people from each age group. (a) Construct a 95% confidence interval for the proportion of people in the 18–24 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 25–34 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 35–49 age group who own at least one credit card. (Round your answers to four decimal places.) to Construct a 95% confidence interval for the proportion of people in the 50+ age group who own at least one credit card. (Round your answers to four…In a study designed to determine whether there was a cluster of brain cancer cases at a Pratt & Whitney plant, record from 223,000 employees were studied and 723 employees with brain tumors were found. Treat those employees as a random sample and construct a 95% confidence interval estimate of the proportion of all adults who develop such tumors. write a brief statement interpreting that confidence interval.A study of 420,039 cell phone users found that 131 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0443% for those not using cell phones. Complete parts (a) and (b). ..... a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. • D%According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data. Also, conduct a hypothesis, with alpha = 0.05, test to determine if these data provide strong evidence the rate of sleep deprivation is different for the two states. Construct a 95% confidence interval Which of the following correctly displays the standard error? 0.0046 0.009 0.001 0.00002 0.008A study of 420,097 cell phone users found that 137 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0311% for those not using cell phones. Complete parts (a) and (b). .... a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
Probability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
Elementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSON
The Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. Freeman
Introduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. FreemanMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman