103 kJ + 2HBr(g) = H₂(g) + Br₂(g) K = 5.4 x 10-20 What is the equilibrium constant for the reaction when it is altered as below? H₂(g) + Br₂(g) 103 kJ + 2HBr(g) K' = [?] x 10?] Coefficient (green) Exponent (yellow) Enter

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### Determining the Equilibrium Constant for an Altered Chemical Reaction

**Given Reaction:**

\[ \text{103 kJ} + 2 \text{HBr}(g) \rightleftharpoons \text{H}_2(g) + \text{Br}_2(g) \]
\[ K = 5.4 \times 10^{-20} \]

**Problem:**

What is the equilibrium constant for the reaction when it is altered as below?

**Altered Reaction:**

\[ \text{H}_2(g) + \text{Br}_2(g) \rightleftharpoons \text{103 kJ} + 2 \text{HBr}(g) \]

\[ K' = \boxed{\textcolor{green}{?}} \times 10^{\textcolor{yellow}{?}} \]

**Instructions:**

- Enter the Coefficient (green) and Exponent (yellow) into the respective fields.
- Press "Enter" to submit your answer.

This content helps students understand how to calculate the new equilibrium constant when a reaction is reversed. The initial equilibrium constant \(K\) is provided for the forward reaction, and students must determine the new constant \(K'\) for the reverse reaction.
Transcribed Image Text:--- ### Determining the Equilibrium Constant for an Altered Chemical Reaction **Given Reaction:** \[ \text{103 kJ} + 2 \text{HBr}(g) \rightleftharpoons \text{H}_2(g) + \text{Br}_2(g) \] \[ K = 5.4 \times 10^{-20} \] **Problem:** What is the equilibrium constant for the reaction when it is altered as below? **Altered Reaction:** \[ \text{H}_2(g) + \text{Br}_2(g) \rightleftharpoons \text{103 kJ} + 2 \text{HBr}(g) \] \[ K' = \boxed{\textcolor{green}{?}} \times 10^{\textcolor{yellow}{?}} \] **Instructions:** - Enter the Coefficient (green) and Exponent (yellow) into the respective fields. - Press "Enter" to submit your answer. This content helps students understand how to calculate the new equilibrium constant when a reaction is reversed. The initial equilibrium constant \(K\) is provided for the forward reaction, and students must determine the new constant \(K'\) for the reverse reaction.
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