= 10.2. Suppose that a reaction A + 2B = 2Y + 2Z is believed to occur according to the mechanism A → 2X (very rapid equilibrium) k₂ X + B Y + Z (slow) Obtain an expression for the rate of formation of the product Y.
= 10.2. Suppose that a reaction A + 2B = 2Y + 2Z is believed to occur according to the mechanism A → 2X (very rapid equilibrium) k₂ X + B Y + Z (slow) Obtain an expression for the rate of formation of the product Y.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![### Reaction Mechanism Analysis
#### Problem 10.2:
Suppose that a reaction \( A + 2B = 2Y + 2Z \) is believed to occur according to the mechanism:
\[ A \xrightarrow{k_1} 2X \quad (\text{very rapid equilibrium}) \]
\[ X + B \xrightarrow{k_2} Y + Z \quad (\text{slow}) \]
**Task: Obtain an expression for the rate of formation of the product Y.**
### Detailed Diagram Description
- The diagram presents a two-step reaction mechanism.
- The first step shows a reactant \( A \) converting into \( 2X \) with a rate constant \( k_1 \). This step is characterized by very rapid equilibrium.
- The second step involves the intermediate \( X \) reacting with \( B \) to form products \( Y \) and \( Z \) with a rate constant \( k_2 \). This step is considered slow, indicating it is the rate-determining step of the overall reaction.
### Rate of Formation of Product Y
To find the expression for the rate of formation of \( Y \), we need to consider the slow step in the mechanism:
\[ X + B \rightarrow Y + Z \]
Since this is the rate-determining step, the rate of formation of \( Y \) depends on the concentration of \( X \) and \( B \):
\[ \text{Rate}_{Y} = k_2 [X][B] \]
However, since \( [X] \) is produced in the first step and is in rapid equilibrium with \( A \):
\[ A \xrightarrow{k_1} 2X \]
We can assume the concentration of \( X \) reaches a steady state quickly. Therefore, we can express \( [X] \) in terms of \( [A] \), and substitute this into the rate equation for \( Y \).
Finalizing the equations and solving to derive the exact expression for \( [Y] \) requires additional steps in kinetics and equilibrium assumptions, often involving \( k_1 \) being much larger compared to \( k_2 \). The detailed kinetic derivation is left as an exercise.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa50af9e4-75d3-4302-8305-ec9f1eb44db0%2Ffac358a8-e95b-4b6c-992d-847eae0ed919%2F18s7qf6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Mechanism Analysis
#### Problem 10.2:
Suppose that a reaction \( A + 2B = 2Y + 2Z \) is believed to occur according to the mechanism:
\[ A \xrightarrow{k_1} 2X \quad (\text{very rapid equilibrium}) \]
\[ X + B \xrightarrow{k_2} Y + Z \quad (\text{slow}) \]
**Task: Obtain an expression for the rate of formation of the product Y.**
### Detailed Diagram Description
- The diagram presents a two-step reaction mechanism.
- The first step shows a reactant \( A \) converting into \( 2X \) with a rate constant \( k_1 \). This step is characterized by very rapid equilibrium.
- The second step involves the intermediate \( X \) reacting with \( B \) to form products \( Y \) and \( Z \) with a rate constant \( k_2 \). This step is considered slow, indicating it is the rate-determining step of the overall reaction.
### Rate of Formation of Product Y
To find the expression for the rate of formation of \( Y \), we need to consider the slow step in the mechanism:
\[ X + B \rightarrow Y + Z \]
Since this is the rate-determining step, the rate of formation of \( Y \) depends on the concentration of \( X \) and \( B \):
\[ \text{Rate}_{Y} = k_2 [X][B] \]
However, since \( [X] \) is produced in the first step and is in rapid equilibrium with \( A \):
\[ A \xrightarrow{k_1} 2X \]
We can assume the concentration of \( X \) reaches a steady state quickly. Therefore, we can express \( [X] \) in terms of \( [A] \), and substitute this into the rate equation for \( Y \).
Finalizing the equations and solving to derive the exact expression for \( [Y] \) requires additional steps in kinetics and equilibrium assumptions, often involving \( k_1 \) being much larger compared to \( k_2 \). The detailed kinetic derivation is left as an exercise.
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