10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hz(g. 1.00 atm) | HCl(aq, 0.100 m) AgCl(s) | Ag(s) is described by the equation: E(V)=0.35510-3.422-105 T-3.2347×10 T²+6.314×10° T where T is the temperature on the Celsius scale. Calculate A,5° for the cell reaction at 50°C. a) -29.9 J/mol.°C b)-33.4 J/mol.°C c) -25.2 J/mol.°C -18.6 J/mol C
10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hz(g. 1.00 atm) | HCl(aq, 0.100 m) AgCl(s) | Ag(s) is described by the equation: E(V)=0.35510-3.422-105 T-3.2347×10 T²+6.314×10° T where T is the temperature on the Celsius scale. Calculate A,5° for the cell reaction at 50°C. a) -29.9 J/mol.°C b)-33.4 J/mol.°C c) -25.2 J/mol.°C -18.6 J/mol C
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hz(g. 1.00 atm) | HCl(aq, 0.100
m) | AgCl(s) | Ag(s) is described by the equation:
E(V)=0.35510-3.422-105 T-3.2347×10 T²+ 6.314×10° T'
where T is the temperature on the Celsius scale. Calculate A,Sº for the cell reaction at
50.°C.
a) -29.9 J/mol °C
b)-33.4 J/mol C
c) -25.2 J/mol.°C
-18.6J/mol C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33291393-a9b1-4d31-ba44-693ed2744b06%2F459400f4-621f-4433-8db3-163089770a3e%2F1e18rnw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hz(g. 1.00 atm) | HCl(aq, 0.100
m) | AgCl(s) | Ag(s) is described by the equation:
E(V)=0.35510-3.422-105 T-3.2347×10 T²+ 6.314×10° T'
where T is the temperature on the Celsius scale. Calculate A,Sº for the cell reaction at
50.°C.
a) -29.9 J/mol °C
b)-33.4 J/mol C
c) -25.2 J/mol.°C
-18.6J/mol C
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