10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hg. 1.00 atm) | HCl(aq, 0.100 m)| AgCl(s) | Ag(s) is described by the equation: E(V)-0.35510-3.422x105 T-3.2347×10 T²+6.314×10⁹T¹ where T is the temperature on the Celsius scale. Calculate 4,50 for the cell reaction at 50°C. a) -29.9 J/mol.°C b)-33.4 J/mol C c) -25.2 J/mol.°C -18.6 J/mol.C
10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hg. 1.00 atm) | HCl(aq, 0.100 m)| AgCl(s) | Ag(s) is described by the equation: E(V)-0.35510-3.422x105 T-3.2347×10 T²+6.314×10⁹T¹ where T is the temperature on the Celsius scale. Calculate 4,50 for the cell reaction at 50°C. a) -29.9 J/mol.°C b)-33.4 J/mol C c) -25.2 J/mol.°C -18.6 J/mol.C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:10. Between 0°C and 90°C, the potential of the cell Pt(s) | Hg. 1.00 atm) | HCK(aq, 0.100
m)| AgCl(s) | Ag(s) is described by the equation:
E(V)-0.35510-3.422x10 T-3.2347x106 T2+ 6.314*10⁹T¹
where T is the temperature on the Celsius scale. Calculate A,S for the cell reaction at
50.C.
a) -29.9 J/mol .°C b) -33.4 J/mol °C
c) -25.2 J/mol.°C
)-18.6 J/mol.C
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