Homework Help is Here – Start Your Trial Now!
Science
Chemistry
In the temperature range 0-90 ºC , the potential difference of the following cell: Pt (s) | H2 (g, f = 1) | HCl (aq, m = 0.1) | AgCl (s) | Ag (s) changes as follows with the temperature: Ecell (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8t2 + 6.314x10-9t3 (t being the temperature in ºC) Write the reaction and calculate ΔG, ΔH and ΔS at 90 ºC. Result: -34388 J/mol, 10.94 J/Kmol, -30.42 KJ/mol

In the temperature range 0-90 ºC , the potential difference of the following cell: Pt (s) | H2 (g, f = 1) | HCl (aq, m = 0.1) | AgCl (s) | Ag (s) changes as follows with the temperature: Ecell (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8t2 + 6.314x10-9t3 (t being the temperature in ºC) Write the reaction and calculate ΔG, ΔH and ΔS at 90 ºC. Result: -34388 J/mol, 10.94 J/Kmol, -30.42 KJ/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question

 In the temperature range 0-90 ºC , the potential difference of the following cell:
Pt (s) | H2 (g, f = 1) | HCl (aq, m = 0.1) | AgCl (s) | Ag (s)
changes as follows with the temperature:
Ecell (V) = 0.35510 – 0.3422x10-4t - 3.2347x10-8t2 + 6.314x10-9t3 (t being the temperature in ºC) Write the reaction and calculate ΔG, ΔH and ΔS at 90 ºC.
Result: -34388 J/mol, 10.94 J/Kmol, -30.42 KJ/mol 

Pt (s) | H2 (g, f= 1)| HCl (aq, m = 0.1)| AgCl (s) | Ag (s) changes as follows with the temperature: Epila (V) = 0.35510 – 0.3422x104t - 3.2347x10-82 + 6.314x10-f³ (t being the temperature in °C) Write the reaction and calculate AG, AH and AS at 90 °C. Result: -34388 J/mol, 10.94 J/Kmol, -30.42 KJ/mol
Transcribed Image Text:Pt (s) | H2 (g, f= 1)| HCl (aq, m = 0.1)| AgCl (s) | Ag (s) changes as follows with the temperature: Epila (V) = 0.35510 – 0.3422x104t - 3.2347x10-82 + 6.314x10-f³ (t being the temperature in °C) Write the reaction and calculate AG, AH and AS at 90 °C. Result: -34388 J/mol, 10.94 J/Kmol, -30.42 KJ/mol
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Activities
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS