4. The standard electromotive force of the cell Pt(s) H2(g)|HCl(aq)|AgCl(s)|Ag(s) has beendetermined from 0°C to 90°C, and the data were found to fit the expressionE*/V = 0.237-4.856 × 10-4T(°C) - 3.421 × 10-T²(°C) + 5.869 × 10-ºT³ (°C)Calculate the equilibrium constant, the standard reaction Gibbs energy, entropy andenthalpy for the cell reaction at 25°C. F = 96485 C mol-¹AgCl(s) + H2(g) → Ag(s) + HCl(aq)

Answered: Image /qna-images/answer/db60ffb8-0347-44db-ba23-f55d4c4442e4.jpg

Answered: 4. The standard electromotive force of…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter17: Electrochemistry And Its Applications

Section: Chapter Questions

Problem 38QRT

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Table 17-1 lists common half-reactions along with the standard reduction potential associated with each half-reaction. These standard reduction potentials are all relative to some standard. What is the standard (zero point)? lf is positive for a half-reaction, what does it mean? If is negative for a half-reaction, what does it mean? Which species in Table 17-1 is most easily reduced? Least easily reduced? The reverse of the half-reactions in Table 17-1 are the oxidation half-reactions. How are standard oxidation potentials determined? In Table 17-1, which species is the best reducing agent? The worst reducing agent? To determine the standard cell potential for a redox reaction, the standard reduction potential is added to the standard oxidation potential. What must be true about this sum if the cell is to be spontaneous (produce a galvanic cell)? Standard reduction and oxidation potentials are intensive. What does this mean? Summarize how line notation is used to describe galvanic cells.
The standard electromotive force of the cell Pt(s)|H2(g)|HCl(aq)|AgCl(s)|Ag(s) has been determined from 0°C to 90°C, and the data were found to fit the expression E/V = 0.237 – 4.856 × 10−4T(°C) − 3.421 × 10−6T2(°C) + 5.869 × 10−9T3(°C) Calculate the equilibrium constant, the standard reaction Gibbs energy, entropy and enthalpy for the cell reaction at 25°C. F = 96485 C mol-1 AgCl(s) + ½H2(g) → Ag(s) + HCl(aq)
The cell potential E for the cell Pt(s) | H2(g, =1.00) | H(aq, =1.00) | NaCl(aq, 0.300 m) | AgCl(s) | Ag(s) at 25°C is +0.260 V. Determine the mean activity coefficient Y+.
Consider the cell, Zn(s)|ZnCl2(0.0050 mol kg−1)|Hg2Cl2(s)|Hg(l), for which the cell reaction is Hg2Cl2(s) + Zn(s) → 2 Hg(l) + 2 Cl−(aq) + Zn2+(aq). The cell potential is +1.2272 V, E⦵(Zn2+,Zn) = −0.7628 V, and E⦵(Hg2Cl2,Hg) = +0.2676 V. (a) Write the Nernst equation for the cell. Determine (b) the standard cell potential, (c) ΔrG, ΔrG⦵, and K for the cell reaction, (d) the mean ionic activity and activity coefficient of ZnCl2 from the measured cell potential, and (e) the mean ionic activity coefficient of ZnCl2 from the Debye–Hückel limiting law. (f) Given that (∂Ecell/∂T)p = −4.52 × 10−4 V K−1, Calculate ΔrS and ΔrH.
The electromotive force of the cell Pb(s) PbSO4(s) Na2SO4.10H₂O(aq)|Hg2SO4(s) Hg() is 0.9647 V at 25 °C. The temperature coefficient is 1.74 x 10-4 V K-¹. What is the AH for the reaction in kJ mol-¹? Express your answer in four significant figures.
Consider the cell, Zn(s)|ZnCl2(0.0050 mol kgHg2Cl2(s)|Hg(I), for which the cell reaction is Hg2Cl2(s) + Zn(s) → 2Hg(1) + 2C1(aq) + Zn2+(aq). The cell potential is +1.2272 v, Ee(Zn²*,Zn) -0.7628 V, and Ee(Hg2Cl2,Hg) = +0.2676 V. (a) Write the Nernst equation for the cell. Determine (b) the standard cell potential, (c) A,G, A,GE, and K for the cell reaction
3) Consider the cell Pt|H2(g)| HCI(aq)|AgCI(s)|Ag, for which the cell reaction is 2 AgCI(s) + H2(g) → 2 Ag(s) + 2 HCl(aq). At 25 °C and a molality of HCl of 0.020 mol kg, Ecell = +0.4658 V. (i) Write the Nernst equation for the cell reaction. (ii) Calculate A,G for the cell reaction. (iii) Assuming that the Debye-Hückel limiting law holds at this concentration, calculate E°(CI", AgCI, Ag).
Tabulated thermodynamic data can be used to predict the standard potential of a cell even if it cannot be measured directly. The standard Gibbs energy of the reaction K2CrO4(aq) + 2 Ag(s) + 2 FeCl3(aq) → Ag2CrO4(s) + 2 FeCl2(aq) + 2 KCl(aq) is −62.5 kJ mol−1 at 298 K. (a) Calculate the standard potential of the corresponding galvanic cell and (b) the standard potential of the Ag2CrO4/Ag,CrO42− couple.
Determine the emf for the cell Ag (s) | AgCl (s) | HCl (a = 1) | Cl2 (1 atm) | Pt given that the standard electrode potential of the Ag (s) | AgCl (s) | Cl- (aq) electrode is 0.2225 V, and that of the Pt | Cl2 (g) | Cl- (aq) is 1.3595 V.[1.137] The answer is written in the bracket. I would like to know how it is obtained. Thank you!
Calculate the standard Gibbs energies at 25 °C of the following reactions from the standard potential data.(a) Ca(s) + 2 H2O(I) → Ca(OH)2(aq) + H2(g)(b) 2 Ca(s) + 4 H2O(I) → 2 Ca(OH)2(aq) + 2H2(g)(c) Fe(s) + 2 H2O(I) → Fe(OH)2(aq) + H2(g)(d) Na2S2O8(aq) + 2 Nal(aq) → 12(s) + 2 Na2SO4(aq)(e) Na2S2O8(aq) + 2 Kl(aq) → l2(s) + Na2SO4(aq) + K2SO4(aq)(f) Pb(s) + Na2CO3(aq) → PbCO3(aq) + 2 Na(s)
Calculate the standard potential of the cell Ag(s)|AgNO3(aq)||Cu(NO3)2(aq)|Cu(s) and the standard Gibbs energy and enthalpy of the cell reaction at 25 °C. (ii) Estimate the value of A,GE at 35 °C.
Consider the following electrochemical cell at 25 C: Pt|H2(g,p)|HCl(aq), 0.010 mol.kg-1|AgCl(s)|Ag For this cell the cell reaction is as follows: 2AgCl(s) + H2(g)  2Ag(s) + 2HCl(aq) (a) Give the electrode half-reactions and determine the standard cell potential.

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