10. A solution of nitrous acid has a pH of 2.10. What is the concentration of nitrous acid in this solution? The Ka of nitrous acid is 7.1 x 104. > A-(1,94x10) = (7.94 x 10j* (7.1 xio4) = 0.0888 (3 s E HNO, Ho + NO CH] = 10 2:10 =794 x lo (35 8) . 0.0888 M Ka = =71x10 CHNO,J (7.94 KIs)* A-(7.94 xi6") A- =) 11 alution of horbiturio agid he of 4 20 W/bot is the congen borbiturie agid the
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
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![10. A solution of nitrous acid has a pH of 2.10. What is the concentration of nitrous acid in this solution?
The Ka of nitrous acid is 7.1 x 104.
(7.94 x 10)*
(7.1 X104)
=> A- (1.94x10)
= 0.0888 (3 s S.)
HNO2
[H] = 10
-2.10
= 7. 94 x 10 (35t)
+ NO2
. 0.0888 M
A
ka =
71x104
it
CHNO,J
(7.94 KIo)
-)
A-
A-(7,94 xio")
11. A solution of barbituric acid has a pH of 4.20. What is the concentration of barbituric acid in the
solution? The pKa of barbituric acid, HC4H3N2O3, is 4.01.
4.20
CH] =
10
= 6.31 x10
CHAJ =
9-7 x lo
= 4.08 x10 MC3 sf.)
Ka =
10
-401
= 9.77 x105
(6.31 xio)*
CHA]
CHAJ
12. What is the pH of a 0.300 M solution of sodium phenolate, NaC6HsO? The Ka of phenol is
1.3 x 10-10
13. How many grams of sodium formate must be added to 100.00 mL of a 0.125M formic acid solution
to achieve a pH of 4.90? The pKa of formic acid is 3.74.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca7f3c27-2cdc-4476-b4cd-eb4e58279a44%2F8c6973f3-75bc-48d0-a303-307e96e2173e%2Fhy6j8v_processed.jpeg&w=3840&q=75)
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