10. A genetic experiment involving peas yielded one sample of offspring consisting of 410 green peas and 174 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p= 0.27 H:p<0.27 O B. Ho: p#0.27 H,: p= 0.27 O C. Ho: p#0.27 O D. Ho: p 0.27 H:p<0.27 H:p>0.27 O E. Ho: p=0.27 OF. Ho p=0.27 H,: p#0.27 H,:p>0.27 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. O D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. O B. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. O C. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. O D. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.

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10. A genetic experiment involving peas yielded one sample of offspring consisting of 410 green peas and 174 yellow peas.
Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow.
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to
the binomial distribution.
What are the null and alternative hypotheses?
O A. Ho: p= 0.27
O B. Ho: p#0.27
H,: p<0.27
H: p = 0.27
O C. Ho: p#0.27
O D. Ho: p#0.27
H;: p>0.27
H1: p<0.27
OF. Ho: p=0.27
O E. Ho: p= 0.27
H,:p#0.27
H;: p> 0.27
What is the test statistic?
(Round to two decimal places as needed.)
What is the P-value?
P-value =
(Round to four decimal places as needed.)
What is the conclusion about the null hypothesis?
O A. Reject the null hypothesis because the P-value is greater than the significance level, a.
O B. Reject the null hypothesis because the P-value is less than or equal to the significance level,
OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance
level, a.
D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
What is the final conclusion?
O A. There is not sufficient evidence to support the claim that less than 27% of offspring peas will
be yellow.
O B. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be
yellow.
C. There is sufficient evidence to support the claim that less than 27% of offspring peas will be
yellow.
O D. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will
be yellow.
Transcribed Image Text:10. A genetic experiment involving peas yielded one sample of offspring consisting of 410 green peas and 174 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p= 0.27 O B. Ho: p#0.27 H,: p<0.27 H: p = 0.27 O C. Ho: p#0.27 O D. Ho: p#0.27 H;: p>0.27 H1: p<0.27 OF. Ho: p=0.27 O E. Ho: p= 0.27 H,:p#0.27 H;: p> 0.27 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Reject the null hypothesis because the P-value is greater than the significance level, a. O B. Reject the null hypothesis because the P-value is less than or equal to the significance level, OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. D. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. What is the final conclusion? O A. There is not sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. O B. There is sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow. C. There is sufficient evidence to support the claim that less than 27% of offspring peas will be yellow. O D. There is not sufficient evidence to warrant rejection of the claim that 27% of offspring peas will be yellow.
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