Today due to COVID-19 virus pandemic in the USA, full-time college students report spending a mean of 20 hours per week on academic activities from home. Assume the standard deviation of time spent on academic activities is 3 hours. If you select a random sample of 50 full-time college students. Find the mean and standard deviation of the sampling distribution (the standard error) of "for a random sample of 50 full-time college students. Round standard error to four decimal places and use this rounded value for the rest of the question. Ⓒa.μ=2.8284 b.μ=2.8284 %=0.4243 C-A=20 d.μ=20 a=0.4243

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Today due to COVID-19 virus pandemic in the USA, full-time college students report spending a mean of 20 hours per week on academic activities from home. Assume the standard deviation of time spent on academic activities is 3 hours. If you
select a random sample of 50 full-time college students.
Find the mean and standard deviation of the sampling distribution (the standard error) of for a random sample of 50 full-time college students. Round standard error to four decimal places and use this rounded value for the rest
of the question.
_=2.8284
a. μ====
0=3
b.μ = 2.8284
-=0.4243
c. μ-=20
0_=3
X
d.μ = 20
o_=0.4243
X
Transcribed Image Text:Today due to COVID-19 virus pandemic in the USA, full-time college students report spending a mean of 20 hours per week on academic activities from home. Assume the standard deviation of time spent on academic activities is 3 hours. If you select a random sample of 50 full-time college students. Find the mean and standard deviation of the sampling distribution (the standard error) of for a random sample of 50 full-time college students. Round standard error to four decimal places and use this rounded value for the rest of the question. _=2.8284 a. μ==== 0=3 b.μ = 2.8284 -=0.4243 c. μ-=20 0_=3 X d.μ = 20 o_=0.4243 X
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