1.The capacitance depends on the size and position of the two conductors. What then do we mean when we say C is constant? 2.If the voltage across a fixed capacitor is doubled, what will be the amount of the energy the capacitor stores?
1.The capacitance depends on the size and position of the two conductors. What then do we mean when we say C is constant? 2.If the voltage across a fixed capacitor is doubled, what will be the amount of the energy the capacitor stores?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 50P: Two capacitors, C1 = 18.0 F and C2 = 36.0 F, are connected in series, and a 12.0-V battery is...
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![### Questions on Capacitance and Energy Stored in a Capacitor
1. **The capacitance depends on the size and position of the two conductors. What then do we mean when we say C is constant?**
2. **If the voltage across a fixed capacitor is doubled, what will be the amount of the energy the capacitor stores?**
---
When explaining the graphs, concepts, or diagrams related to the above questions, ensure to detail the relation between the physical characteristics of capacitors and their capacitance, as well as the mathematical relationship between voltage and stored energy.
**Explanatory Points for the Educational Website:**
1. **Capacitance and its Dependence on Physical Properties:**
- Capacitance (\(C\)) is influenced by the physical characteristics of the capacitor, such as the area of the conductors, the distance between them, and the dielectric material.
- When \(C\) is said to be constant, it implies that the physical attributes (size, distance, material) of the capacitor do not change.
2. **Energy Stored in a Capacitor with Changing Voltage:**
- The energy (\(W\)) stored in a capacitor is given by the formula \( W = \frac{1}{2}C V^2 \).
- If the voltage (\(V\)) is doubled, the energy stored becomes \( W' = \frac{1}{2}C (2V)^2 = 4 \times \frac{1}{2}C V^2 \), which means the energy stored increases fourfold.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71886d56-a83a-4d7b-8e18-9a0e9bdd4c82%2F5d521280-c664-430d-be3b-045835c2fb22%2Fugk5kpn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Questions on Capacitance and Energy Stored in a Capacitor
1. **The capacitance depends on the size and position of the two conductors. What then do we mean when we say C is constant?**
2. **If the voltage across a fixed capacitor is doubled, what will be the amount of the energy the capacitor stores?**
---
When explaining the graphs, concepts, or diagrams related to the above questions, ensure to detail the relation between the physical characteristics of capacitors and their capacitance, as well as the mathematical relationship between voltage and stored energy.
**Explanatory Points for the Educational Website:**
1. **Capacitance and its Dependence on Physical Properties:**
- Capacitance (\(C\)) is influenced by the physical characteristics of the capacitor, such as the area of the conductors, the distance between them, and the dielectric material.
- When \(C\) is said to be constant, it implies that the physical attributes (size, distance, material) of the capacitor do not change.
2. **Energy Stored in a Capacitor with Changing Voltage:**
- The energy (\(W\)) stored in a capacitor is given by the formula \( W = \frac{1}{2}C V^2 \).
- If the voltage (\(V\)) is doubled, the energy stored becomes \( W' = \frac{1}{2}C (2V)^2 = 4 \times \frac{1}{2}C V^2 \), which means the energy stored increases fourfold.
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