I need help with Q 3 please ### Capacitance and Energy Storage in Capacitors#### 1. Determine Capacitance and EnergyChoose plate separation: 2.0 mmPlate area: 100 mm²Voltage: 0.5 VWhat is the value of the capacitance? What is the value of the energy stored?- Capacitance (C2) = - Energy (E2) = Verify your answers.---#### 2. Effect of Varying Plate Separation on CapacitanceRepeat the calculation in Step 1 by changing the plate separation to 4, 6, and 8 mm (while keeping the plate area and voltage the same as in Step 1).- Capacitance with 4 mm separation (C4) = Energy (E4) =- Capacitance with 6 mm separation (C6) = Energy (E6) =- Capacitance with 8 mm separation (C8) = Energy (E8) =---#### 3. Effect of Varying Plate Area on CapacitanceRepeat the calculation in Step 1 by changing the plate area to 200, 300, and 400 mm² (while keeping the plate separation and voltage the same as in Step 1).- Capacitance with 200 mm² plate area (C200) = Energy (E200) =- Capacitance with 300 mm² plate area (C300) = Energy (E300) =- Capacitance with 400 mm² plate area (C400) = Energy (E400) =---### Explanation of Concepts1. **Capacitance (C):** Capacitance is the ability of a system to store an electric charge. For a parallel plate capacitor, the capacitance is given by the formula: \[ C = \frac{ε_0 \times A}{d} \] where \(ε_0\) is the permittivity of free space (8.85 x 10⁻¹² F/m), \(A\) is the area of one of the plates, and \(d\) is the separation between the plates.2. **Energy (E):** The energy stored in a capacitor is given by the formula: \[ E = \frac{1}{2} C V^2

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Answered: 3.Repeat 1, by changing the plate area…

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3.Repeat 1, by changing the plate area to 200, 300 and 400 mm² (keep plate separation and voltage as in 1).

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I need help with Q 3 please

### Capacitance and Energy Storage in Capacitors

#### 1. Determine Capacitance and Energy
Choose plate separation: 2.0 mm
Plate area: 100 mm²
Voltage: 0.5 V

What is the value of the capacitance? What is the value of the energy stored?
- Capacitance (C2) =
- Energy (E2) =

Verify your answers.

---

#### 2. Effect of Varying Plate Separation on Capacitance
Repeat the calculation in Step 1 by changing the plate separation to 4, 6, and 8 mm (while keeping the plate area and voltage the same as in Step 1).

- Capacitance with 4 mm separation (C4) = Energy (E4) =
- Capacitance with 6 mm separation (C6) = Energy (E6) =
- Capacitance with 8 mm separation (C8) = Energy (E8) =

---

#### 3. Effect of Varying Plate Area on Capacitance
Repeat the calculation in Step 1 by changing the plate area to 200, 300, and 400 mm² (while keeping the plate separation and voltage the same as in Step 1).

- Capacitance with 200 mm² plate area (C200) = Energy (E200) =
- Capacitance with 300 mm² plate area (C300) = Energy (E300) =
- Capacitance with 400 mm² plate area (C400) = Energy (E400) =

---

### Explanation of Concepts

1. **Capacitance (C):**
Capacitance is the ability of a system to store an electric charge. For a parallel plate capacitor, the capacitance is given by the formula:

\[
C = \frac{ε_0 \times A}{d}
\]

where \(ε_0\) is the permittivity of free space (8.85 x 10⁻¹² F/m), \(A\) is the area of one of the plates, and \(d\) is the separation between the plates.

2. **Energy (E):**
The energy stored in a capacitor is given by the formula:

\[
E = \frac{1}{2} C V^2

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