Q 2 please I need help Data TableMass of cart: 5kg.Mass of bar: 98 kg.M₁ = Mass of cart + Mass of bar: 0.6 kgMass of 'weight hanger': 0,5kg.Note: M₂= mass of 'weight hanger'+ added massesTrial #12345678910M₂(kg)0.100.150.200.290.30Acceleration a(m/s2)0300346X0.550.008060XlD=40.11310.162±0.20610.00190.0019100.00240.24910.390.400.299±0.45 0.333±0.500.00444X10-45.9x10-40.387+5.9x10-40.4288.7x10²4(M₁+ M₂).a(N) Phys2425QUESTIONS1. Show the slope calculation of g (using proper units) and calculate the % error ofyour experimental value.2. What are the major sources of error?

There is a variation in acceleration while the masses are fix. Therefore, the force can be…

Mass of cart: 5 kg. Mass of bar: 4.98 kg. M₁ = Mass of cart + Mass of bar 0.16 kg Mass of 'weight hanger": 0,5kg. Note: M₂= mass of 'weight hanger' + added masses Trial # 1 2 3 4 5 6 7 8 9 10 M₂ (kg) 0.10 0.15 0.20 0.29 0.30 Acceleration a (m/s²) 10300346X 0.0080 60x154 0.1131 0.162+ 0.2061 0.0019 6.0019 20024 0.249 + 0.39 0.40 0.299± 0-45 2.606 4404 0.333 ± 5.9X1D-4 0.50 0.387+ 5.9x10-4 0.55 0.428 8.7x10²4 -4 (M₁ + M₂). a (N)