1.A 675-N Marine in basic training climbs a 10.5-m vertical rope at a constant speed in 9.25 s. What is his power output? w
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1.A 675-N Marine in basic training climbs a 10.5-m vertical rope at a constant speed in 9.25 s. What is his power output? w
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- 8. DETAILS SERPSE10 8.5.OP.017. MY NOTES ASK YOUR TEACHER A 650-N Marine in basic training climbs a 11.5-m vertical rope at a constant speed in 6.00 s. What is his power output? WAn elevator is designed so that when it travels upward, it has constant acceleration from rest to its cruising speed of 2.0 m/s in a time of 4.0 seconds. The elevator has a mass of 625kg. Assume friction is ignored. A. Determine the average power (in W) of the elevator motor while its accelerating upward to its cruising speed. B. Determine the motor power (in W) when the elevator is moving upward at its cruising speed.3. A 26.00-kg child initially at rest slides down a playground slide from a height of 3.20 m above the bottom of the slide. If her speed at the bottom is 2.80 m/s, how much energy is lost due to friction? J cci16 f16 cci16 ceil6 cci
- If a ski lift raises 150 passengers averaging 690 N in weight to a height of 126 m in 45.9 s, at constant speed, what average power is required of the force making the lift? Number i 270096 eTextbook and Media Units W24. A skier of mass 70 kg is pulled up a slope by a motor-driven cable. How many horsepower output must a motor have to pull him 100 m up a 30° frictionless slope at a constant speed of 2 m/s? a.700 b. 0.94 c. 746 d. 1.06 a b dHow much power is expended if you lift a 50 N rock 10 m in 2 seconds? A.250 W B.25 W C.2.5 W D.5 W
- A child pulls a wagon 5.0 m using a force of 25 N at an angle 15 degrees above horizontal. The force of friction on the wagon is 8.1 N. Calculate the work done on the wagon in the horizontal direction. a. 6.5 J b. 24.1 J c. 32.5 J d. 80 J e. 84.5 J f. 125.1 J g. 125 J h. don't be silly, you can't calculate the net work without the change in KE!!In the Figure below, we see a 500 gram block resting on the horizontal portion of a "track", whose left end is curved upwards. The horizontal portion of the track is frictionless, except for a 50.0 cm long “rough" portion, shown in the Figure, where the coefficient of kinetic friction is 0.300. The curved portion of the track is frictionless. The block is held against a spring (which has a stiffness constant of 500 N/m), compressing the spring by 10.0 cm. Then the block is released from rest. (NOTE: The block is not attached to the spring; it is just held against the end of the spring.) For simplicity, assume that g = 9.80 m/2. 50.0 cmA. Find friction. B. Find Gravity.