A girl on a skating board was going to her classroom. She stopped pushing with her foot when she's a bout five meters from the classroom. Letting the friction force slowed her down. The work done by the friction force on the skateboard is time Download from Dreamstime.com negative O some other value O positive zero

A girl on a skating board was going to her classroom. She stopped pushing with her foot when she's a bout five meters from the classroom. Letting the friction force slowed her down. The work done by the friction force on the skateboard is time Download from Dreamstime.com negative O some other value O positive zero

Name: 6.TF.A girl on a skating board was going to her classroom. She stoppe
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Description: 6.TF.A girl on a skating board was going to her classroom. She stopped pushing with her foot whenshe's a bout five meters from the classroom. Letting the friction force slowed her down. Thework done by the friction force on the skateboard isDownload

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem A new type of force was discovered by physicists with the following expression: where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole. Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process) Solution To determine the work done we apply the following W = dx Evaluating the above, we get W = | | + e + x for the limits from xi to xf substituting x1 and x2 as the limits, the work done is expressed as W = | / | + ( x1 - ) + ( x15 - x25 )
Problem A new type of force was discovered by physicists with the following expression: where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole. Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process) Solution To determine the work done we apply the following W = ___ dx Evaluating the above, we get W = ___ | ___ | + ___ e ____ + ___ x ____ for the limits from xi to xf Substituting x1 and x2 as the limits, the work done is expressed as W = ___ | ___ / ___ | + ___ ( ___ x1 - ___ ) + ___ ( x15 - x25 )
an object is acted by a frictional force. the work done by this frictional force is a. negative because friction force is opposite its motion b. zero because fk = ukn and normal force is perpendicular to the motion c. zero because friction is not the cause of its motion d. could be positive, negative or zero because the direction of friction is unknown