Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a ope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out constant 1900 Newtons while Magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a ope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out constant 1900 Newtons while Magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.
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![**Problem Statement:**
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 1900 Newtons while Magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.
**Solution:**
To solve this problem, we will use the formula for work done by a force:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
Where:
- Work is measured in Joules (J).
- Force is measured in Newtons (N).
- Distance is measured in meters (m).
- \( \theta \) is the angle between the force and the direction of motion. For a perfectly horizontal pull, \( \theta = 0^\circ \) and \( \cos(0^\circ) = 1 \).
Given values:
- Force = 1900 N
- Distance = 1.55 m
- \( \theta = 0^\circ \)
Substitute the values into the formula:
\[ \text{Work} = 1900 \, \text{N} \times 1.55 \, \text{m} \times 1 \]
\[ \text{Work} = 2945 \, \text{Joules} \]
Therefore, the tension force does 2945 Joules of work on Magnus.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9081bc6b-9817-477c-9b8d-7c2dcc8c93d8%2F0295ab67-168a-43ce-b801-a1906f2a7473%2Fvf1or8p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 1900 Newtons while Magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.
**Solution:**
To solve this problem, we will use the formula for work done by a force:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
Where:
- Work is measured in Joules (J).
- Force is measured in Newtons (N).
- Distance is measured in meters (m).
- \( \theta \) is the angle between the force and the direction of motion. For a perfectly horizontal pull, \( \theta = 0^\circ \) and \( \cos(0^\circ) = 1 \).
Given values:
- Force = 1900 N
- Distance = 1.55 m
- \( \theta = 0^\circ \)
Substitute the values into the formula:
\[ \text{Work} = 1900 \, \text{N} \times 1.55 \, \text{m} \times 1 \]
\[ \text{Work} = 2945 \, \text{Joules} \]
Therefore, the tension force does 2945 Joules of work on Magnus.
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