8. Find the work done on the block by friction, assuming that the block makes it all of the way through the 50.0 cm long rough portion of the track where friction is significant. A. - 0.0750 J. B. - 1.47 J. C. - 0.735 J. D. 735 J E. - 735 J. 9. Find the work done on the block by the normal force while the block slides along the horizontal portion of the track. A. zero. B. 735 J C. - 1.47 J. D. - 0.0750 J. E. -0. 735 J. 10. Find the work done on the block by gravity while the block slides along the horizontal portion of the track. A. 2.45 J B. - 0. 735 J. C. zero. D. 1.77 J. E. - 1.77 J.
8. Find the work done on the block by friction, assuming that the block makes it all of the way through the 50.0 cm long rough portion of the track where friction is significant. A. - 0.0750 J. B. - 1.47 J. C. - 0.735 J. D. 735 J E. - 735 J. 9. Find the work done on the block by the normal force while the block slides along the horizontal portion of the track. A. zero. B. 735 J C. - 1.47 J. D. - 0.0750 J. E. -0. 735 J. 10. Find the work done on the block by gravity while the block slides along the horizontal portion of the track. A. 2.45 J B. - 0. 735 J. C. zero. D. 1.77 J. E. - 1.77 J.
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Question
Transcribed Image Text:In the Figure below, we see a 500 gram block resting on the horizontal portion of a "track", whose left end is curved upwards.
The horizontal portion of the track is frictionless, except for a 50.0 cm long “rough" portion, shown in the Figure, where the
coefficient of kinetic friction is 0.300. The curved portion of the track is frictionless. The block is held against a spring (which
has a stiffness constant of 500 N/m), compressing the spring by 10.0 cm. Then the block is released from rest. (NOTE: The block
is not attached to the spring; it is just held against the end of the spring.) For simplicity, assume that g = 9.80 m/2.
50.0 cm
Transcribed Image Text:8. Find the work done on the block by friction, assuming that the block makes it all of the way through the 50.0 cm long rough
portion of the track where friction is significant.
A. - 0.0750 J.
B. - 1.47 J.
C. - 0.735 J.
D. 735 J
E. - 735 J.
9. Find the work done on the block by the normal force while the block slides along the horizontal portion of the track.
А.
zero.
В. 735 J
C. - 1.47 J.
D. -0.0750 J.
E. -0. 735 J.
10. Find the work done on the block by gravity while the block slides along the horizontal portion of the track.
A. 2.45 J
B. -0. 735 J.
C. zero.
D. 1.77 J.
E. - 1.77 J.
11. True or False: While the block slides up along the curved portion of the track, the work done on the block by the normal
force equals zero?
A. True.
B. False.
Expert Solution
Step 1
The block is held against one end of the spring, such that the spring is compressed by a distance of 10 cm.
Due to this compression produced in the spring, potential energy gets stored within the spring, given as
As the block is released from the spring, the spring starts getting relaxed, pushing the block forward in the process. As the spring relaxes, the potential energy stored in the spring starts reducing, and as a result, the kinetic energy of the block keeps increasing.
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