17. A force of F-20N at an angle of 37 degrees is applied to a 3-kg object initially at rest. The object has displaced a distance of 25m over a frictionless horizontal table. Determine the work done by (a) The applied force (c) The force of gravity W=20x25 (b) The normal force exerted by the table w=500 (a) = w = 500 399 F: JON Langl w= 9.8/3)*73 15733 25m 20 = cos 3 F: 2010 F₁ 15 W=15.97*25m
17. A force of F-20N at an angle of 37 degrees is applied to a 3-kg object initially at rest. The object has displaced a distance of 25m over a frictionless horizontal table. Determine the work done by (a) The applied force (c) The force of gravity W=20x25 (b) The normal force exerted by the table w=500 (a) = w = 500 399 F: JON Langl w= 9.8/3)*73 15733 25m 20 = cos 3 F: 2010 F₁ 15 W=15.97*25m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:5kg
a. It would take 0 kg of effort to lift the bucket.
b. It would take 2.5 kg of effort to lift the bucket.
It would take 5 kg of effort to lift the bucket.
d. It would take 10 kg of effort to lift the bucket.
15. A pulley makes work easier by
a, increasing force,
b. increasing distance.
changing the direction of force.
d. none of the above.
Show all work to receive credit
W=FXD
16. A constant force of 1200 N is required to push a car along a straight line. A person
displaces the car by 45 m. How much work is done by the person? W= 1200, 45 (W = 54,000)
17. A force of F=20N at an angle of 37 degrees is applied to a 3-kg object initially at
rest. The object has displaced a distance of 25m over a frictionless horizontal table.
Determine the work done by
(a) The applied force
W=20*25
(b) The normal force exerted by the table w=500
(c) The force of gravity
(a) = w = 500
(b) = w=399
(c)=w = 735
F: JON
Engl
(૩-૧૪(૩) ૨૭
W=735
25m
= cos 37
Fx: 20c0537
F-15.97 N
30
W=15.97*25m
W = 399
$$1
$6
€*ME
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