**Physics Problem: Work Done by Gravity****Problem Statement:**Find the work done in joules by gravity as an object of mass \( m = 5 \, \text{kg} \) is raised up at a constant speed from a height \( h_1 = 26 \, \text{m} \) to a height \( h_2 = 69 \, \text{m} \). Consider \( g = 10 \, \text{m/s}^2 \).**Options:**A. NoneB. -2150C. -1075D. -6450E. -4300**Explanation:**To solve for the work done by gravity, we use the formula:\[ W = m \cdot g \cdot \Delta h \]Where:- \( W \) is the work done by gravity,- \( m \) is the mass of the object,- \( g \) is the acceleration due to gravity,- \( \Delta h \) is the change in height (final height \( h_2 \) - initial height \( h_1 \)).Given:\[ m = 5 \, \text{kg} \]\[ g = 10 \, \text{m/s}^2 \]\[ h_1 = 26 \, \text{m} \]\[ h_2 = 69 \, \text{m} \]Calculate the change in height (\( \Delta h \)):\[ \Delta h = h_2 - h_1 \]\[ \Delta h = 69 \, \text{m} - 26 \, \text{m} \]\[ \Delta h = 43 \, \text{m} \]Now, substitute the values into the formula:\[ W = 5 \, \text{kg} \times 10 \, \text{m/s}^2 \times 43 \, \text{m} \]\[ W = 5 \times 10 \times 43 \]\[ W = 2150 \, \text{J} \]Since the object is raised upward, gravity does negative work:\[ W = -2150 \, \text{J} \]Hence, the correct option is:B. -2150

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Description: **Physics Problem: Work Done by Gravity****Problem Statement:**Find the work done in joules by gravity as an object of mass \( m = 5 \, \text{kg} \) is raised up at a constant speed from a height \( h_1 = 26 \, \text{m} \) to a height \( h_2 = 69 \,

Mass of object m = 5 kg Initial height h1 = 26 m Final height h2 = 69 m g = 10 m/s²

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Find the work done in joules by gravity as an object of the mass m 5 kg is raised up at constant speed from a height h;=26 m to a height h2-69 m. Consider g = 10 m/s2

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

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Question

**Physics Problem: Work Done by Gravity**

**Problem Statement:**
Find the work done in joules by gravity as an object of mass \( m = 5 \, \text{kg} \) is raised up at a constant speed from a height \( h_1 = 26 \, \text{m} \) to a height \( h_2 = 69 \, \text{m} \). Consider \( g = 10 \, \text{m/s}^2 \).

**Options:**

A. None

B. -2150

C. -1075

D. -6450

E. -4300

**Explanation:**

To solve for the work done by gravity, we use the formula:

\[ W = m \cdot g \cdot \Delta h \]

Where:
- \( W \) is the work done by gravity,
- \( m \) is the mass of the object,
- \( g \) is the acceleration due to gravity,
- \( \Delta h \) is the change in height (final height \( h_2 \) - initial height \( h_1 \)).

Given:
\[ m = 5 \, \text{kg} \]
\[ g = 10 \, \text{m/s}^2 \]
\[ h_1 = 26 \, \text{m} \]
\[ h_2 = 69 \, \text{m} \]

Calculate the change in height (\( \Delta h \)):
\[ \Delta h = h_2 - h_1 \]
\[ \Delta h = 69 \, \text{m} - 26 \, \text{m} \]
\[ \Delta h = 43 \, \text{m} \]

Now, substitute the values into the formula:
\[ W = 5 \, \text{kg} \times 10 \, \text{m/s}^2 \times 43 \, \text{m} \]
\[ W = 5 \times 10 \times 43 \]
\[ W = 2150 \, \text{J} \]

Since the object is raised upward, gravity does negative work:

\[ W = -2150 \, \text{J} \]

Hence, the correct option is:

B. -2150

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