1.75 g of C:H6 and 6.75 g of Oz are placed in a vessel where they react according to the following balanced equation: 2 C2H6 + 7 O; → 4 CO2 + 6 H;0 i) Determine which substance is the limiting reagent. ii) Calculate the mass (in grams) of the excess reactant remain. iii) Determine the theoritical yield of CO2 in grams. iv) Calculate the theoritical yield of H20 in grams.

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1.75 g of C:H6 and 6.75 g of O2 are placed in a vessel where they react according to the
following balanced equation: 2 C2H6 + 7 O; → 4 CO2 + 6 H;0
i)
Determine which substance is the limiting reagent.
ii) Calculate the mass (in grams) of the excess reactant remain.
iii) Determine the theoritical yield of CO2 in grams.
iv) Calculate the theoritical yield of H20 in grams.
Transcribed Image Text:1.75 g of C:H6 and 6.75 g of O2 are placed in a vessel where they react according to the following balanced equation: 2 C2H6 + 7 O; → 4 CO2 + 6 H;0 i) Determine which substance is the limiting reagent. ii) Calculate the mass (in grams) of the excess reactant remain. iii) Determine the theoritical yield of CO2 in grams. iv) Calculate the theoritical yield of H20 in grams.
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