1.7. A study was conducted to analyse the effect of the size of the deposit level (X₂) and the likelihood that a returnable one-litre bottle will be returned. A return of a bottle recorded as Y = 1and no return Y = 0 was recorded. Use the following table to do a Pearson Chi-Square Goodness of Fit test in order to detect major departures from the logistic response function. That is that the logistic regression is a good fit for the data. ft = [1 + exp(2.077 -0.136X]-¹ Use x²(0.99,df) = 6.63 for a = 0.01, and determine the df-value. j- 2 3 10 15 300 300 80 126 nj Y₁ Complete the following table: ji 1 2 3 لي 1 2 300 50 4 TT₁ P₁ = Y/n Ojo not ret Ejo not ret n-Eji ret 22 300 150 0j1 ret Chi Square= Ej1 ret = 12+ T Totals Totals E (Ojo - Ejo)² Ejo Totals E₁ (0₁₁ - Ej₁)² Ej₁

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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1.7. A study was conducted to analyse the effect of the size of the deposit level (X₂) and the likelihood
that a returnable one-litre bottle will be returned. A return of a bottle recorded as Y = 1and no
return Y = 0 was recorded.
Use the following table to do a Pearson Chi-Square Goodness of Fit test in order to detect major
departures from the logistic response function. That is that the logistic regression is a good fit for
the data.
ft = [1 + exp(2.077 -0.136X]-¹
Use x²(0.99, df) = 6.63 for a = 0.01, and determine the df-value.
2
10
300
80
ji | πι
nj
Yj
Complete the following table:
1
2
3
j=
X₁
4
1
2
300
50
P₁ = Y/n Ojo not ret
3
15
300
126
E jo not ret
n - Ej1 ret
Oj1 ret
Chi Square
22
300
150
=
Ej1 ret
= n* π
Totals
Totals Eo
(Ojo - Ejo)²
Ejo
Totals E₁
(0₁₁ - Ej₁)²
Ej₁
Transcribed Image Text:1.7. A study was conducted to analyse the effect of the size of the deposit level (X₂) and the likelihood that a returnable one-litre bottle will be returned. A return of a bottle recorded as Y = 1and no return Y = 0 was recorded. Use the following table to do a Pearson Chi-Square Goodness of Fit test in order to detect major departures from the logistic response function. That is that the logistic regression is a good fit for the data. ft = [1 + exp(2.077 -0.136X]-¹ Use x²(0.99, df) = 6.63 for a = 0.01, and determine the df-value. 2 10 300 80 ji | πι nj Yj Complete the following table: 1 2 3 j= X₁ 4 1 2 300 50 P₁ = Y/n Ojo not ret 3 15 300 126 E jo not ret n - Ej1 ret Oj1 ret Chi Square 22 300 150 = Ej1 ret = n* π Totals Totals Eo (Ojo - Ejo)² Ejo Totals E₁ (0₁₁ - Ej₁)² Ej₁
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