Answered: 1. Which of the following electric…

1. Which of the following electric field lines are incorrect for point charges? If it is incor explain why. (a) (c) (e) +5μC (g) (b) (d) (1) -5μC

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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2. Three point charges are fixed in place at the corners of a trapezoid as shown. The upper side has length 3.0 cm, the base has length 5.0 cm and the height is 3.0 cm. q, =+ 10.0 nC, 3 cm 92 5. 0 nC, and q, =+ 5.0 nC. 3 cm| a. Find the electric field at point P, the lower left corner of the trapezoid. b. Find the electric potential at point P taking the potential at infinity to be zero. -27 = 1. 67 × 10 kg) c. Suppose a proton (m is placed at point P and is released from rest. What will its speed be when it is very far from the arrangement of charges? P 1 cm 3 ст 1 cm 3.
Two point charges q1 = 2.5 x 10-6C at x = 0 and q2 = -5 x 10-6C at x = 3 m are placed along the x-axis. What is the magnitude and direction of the electric field at x =1.5 m due to q1? ‘ A. 20,000 N/C; right B. 30,000 N/C; right C. 10,000 N/C; right D. 20,000 N/C; left
3. A point charge q1 = 3.00 nC is at the origin. Another charge q2 = - 8.00 nC is at x = 1.00 m. Compute for the net electric field (magnitude and direction) at -0.250 m.4. A particle has a charge of -5.8 nC. (a) What is the magnitude and directionof the electric field due to this particle at 0.30 m directly above it? (b) Whereshould the particle be when the electric field has a magnitude of 18.0 N/C?
Read aloud V Draw Highlig LU: Electric Field KUTNP Using the values given below, find the electric field at point X due to the two charges q, and q2. 92- q1 = 2.8 uC, q2= 4.5 µC, a = 0.57_m, b = 0.22_m, c = 0.61_m magnitude A. 119000_N/C D. 199400 N/C B. 117300 N/C E. 70820 N/C C. 224600 N/C 80990 N/C |-- 6. direction 105° B. C. A. D. 84.17° 91 a, 92 141.5 157.1° 185.4° E. 93.91° F. PORRD In the diagram below, two electric charges q, and g, are positioned as shown, and their corresponding electric field vectors E, and E, at a point are already sketched in the diagram. Find their resultant E E, +E F. 5.
1. A configuration of charges is shown below. q = 5 nC 0 Enet -2q = 5 +q +3q 10 The electric fields due to the charges -2q, +q, +3q, and -q at x = 11 cm are shown below. The direction of the electric field due to a point charge at any point is along the line joining the charge and the point and away from the charge for a positive charge and towards the charge for a negative charge. E x (cm) -E -9 E 20 x= 11 cm The electric fields due to -2q at x = 11 cm is in the negative x-direction, and due to -q, +q and +3q is in the positive x-direction. The strength of the field is determined by the charge and the distance between the charge and the point. The net electric field in Part 1 will point in the positive x-direction. (a) Find the total electric field at x = 11 cm. N C ta E E +34
8. Three point-like charges are placed as shown in the figure, a = 38.0 cm and b = 54.0 cm. The charge (93) is placed +1.80 µC, 92 = -4.20 μC, half way on the (b) side. Find the magnitude of the electric field at the top left corner. Let q₁ and q3 +5.10 μc. N/C 92
Point charges q, = 45 nC, q, = -35 nC, q3 = 25 nC, and q4 = -15 nC are arranged in Figure. (a) Find the electric field at P. (b) Find the magnitude of the electric field at P. (c) Find the direction of the electric field at P. (k = 9×10° N×m²/C², and n = 10-9) y 92 = -35 nC 91 = 45 nC 3 m + Rectangular Snip 3 m →X 3 m P 94 = -15 nC 1 m 93 = 25 nC
2. Planes x=-3, y=6, respectively, carry charges 8 nc/m² and 12 nc/m². If the line x=0, y=3 carries charge 87 nc/m. Find the electric field E at (1, 1,-1).
8. Point charges q₁= +12 nC and q₂= -12 nC are 0.100 m apart (see Figure below). (Such pairs of point charges with equal magnitude and opposite sign are called electric dipoles.) Compute the electric field caused by the field caused by q₁, the field caused by q2 and the total field (a) at point a, (b) at point b, and (c) at point c. E₁ b K 4.0 cm 91 13.0 cm α 6.0 cm a 13.0 cm * 4.0 cm 92 X
6. Please show the full details on the solution
. Two point charges of 5.0 µC are located on the y axis. One is at y = 10 cm, and the other is at y = -10 cm. Determine the total electric field at a point, (50 cm, 0).
2. Three charges are placed on the vertices of an equilateral triangle whose side is 0.025 m. Find the net electric field at the center of the base of the triangle (point P). q1= - 3.0 mC +4.0 nC. q2= -2.0 nC , q3= q1 q2 q3