2) A line of charge with a linear charge density λ extends from -xo to Xxo along the x axis. What is the electric field at a point P located on the y axis a distance y above the x axis? HINT: You'll need the following: dx X 2 (x² +9²) ³/ a ² ( x ² + a ²³) ¹/₂² (from #10 on the integral table in Appendix F of your text) 213/2 =

2) A line of charge with a linear charge density λ extends from -xo to Xxo along the x axis. What is the electric field at a point P located on the y axis a distance y above the x axis? HINT: You'll need the following: dx X 2 (x² +9²) ³/ a ² ( x ² + a ²³) ¹/₂² (from #10 on the integral table in Appendix F of your text) 213/2 =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The electric field at a distance of 0.154 m from the surface of an insulating solid sphere of radius 0.385 m is 1970 N/C. Assuming that the charge on the sphere is uniformly distributed, a) what is the charge density within it? b) Calculate the electric field inside the sphere at a distance of 0.150 m from the center.
3: please help answer this ASAP
+X, to positive infinity. The line carries positive charge with a uniform linear charge density Ao. A continuous line of charge lies along the x axis, extending from x = (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: 1o, xo, and ke.) 0. %3D (b) What is the direction of the electric field at the origin? O +X +y O -z
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My answer is 42.9 cm but it is wrong but the unit CM si correct
Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/ao + B/r + bo %| where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Va Edr= Edr Calculating the antiderivative or indefinite integral, Vab = (-aaoe-r/ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e-"b/ao - era/ao) + B In( ) + bo ( ))
Find the flux in N.m².C-1 of a constant electric field E = (5.3180x10^3) i + (-5.514x10^3)j + (-1.5880x10^3) k N/C, passing through an area defined by the area vector A = (-4.7990x10^0) i + (-7.69x10^0) j + (4.2900x10^-1) k m².
A square metal plate with a thickness of 1.5 cm has no net charge and is placed in a region of uniform electric field 8.0 x 104 N/C directed perpendicularly to the plate. Find the resulting surface charge density on each face of the plate. The answer is E = 0, ? = 7.1 x 10-7 C/m2 I don't know if it is the answer. please show a solution
-->> R In the figure we see a rod of length LA = 22 cm carries a charge QA = 22 nC and a circular arc of radius RB = 13 cm caries a charge QB = 49 nC. The center of the rod is at y = 4 cm from the origin. a) Find the charge density for both the rod and the arc. charge density of the rod Give your answer up to at least three significance digits. C/m charge density of the arc Give your answer up to at least three significance digits. Activa C/m Go to S
Electric Field Integrals
= 3.95 μC. Express your answer in vector form.) The figure below shows three charged spheres arranged along the y axis. (Assume q₁ = 2.90 μC and 92 91 75.0 cm -4.80 μC X 22.0 cm 92 (a) What is the electric field at x = 0, y = 2.80 m? N/C (b) What is the electric field at x = 2.80 m, y = 0? = N/C
A charge of –25 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric field (in N/C) due to this charge at the following distances from the center of the sphere. (Enter the radial component of the electric field.) (a) 7.0 cm E - (0 = (b) 8.0 cm E = (c) 22.0 cm E = X N/C f